Композиционные материалы в технике и перспективы их получения при производстве отливок. Черный А.А - 45 стр.

1560 O(8) = O(8) + (P(J) * K(J)) ^ 2: NEXT J: B(8) = S / O(8): S = 0: O(9) = 0
1570 FOR J = 1 TO X: S = S + K(J) * Q(J) * Y(J): O(9) = O(9) + (K(J) * Q(J)) ^ 2
1580 NEXT J: B(9) = S / O(9): IF X = 9 GOTO 2390
1590 IF X = 27 GOTO 2040
2040 S = 0: O(10) = 0: FOR J = 1 TO X: S = S + U(J) * Y(J)
2050 O(10) = O(10) + U(J) ^ 2: NEXT J: B(10) = S / O(10): S = 0: O(11) = 0
2060 FOR J = 1 TO X: S = S + I(J) * U(J) * Y(J): O(11) = O(11) + (I(J) * U(J)) ^ 2
2070 NEXT J: B(11) = S / O(11): S = 0: O(12) = 0: FOR J = 1 TO X
2080 S = S + P(J) * U(J) * Y(J): O(12) = O(12) + (P(J) * U(J)) ^ 2: NEXT J
2090 B(12) = S / O(12): S = 0: O(13) = 0: FOR J = 1 TO X
2100 S = S + I(J) * P(J) * U(J) * Y(J): O(13) = O(13) + (I(J) * P(J) * U(J)) ^ 2
2110 NEXT J: B(13) = S / O(13): S = 0: O(14) = 0: FOR J = 1 TO X
2120 S = S + V(J) * Y(J): O(14) = O(14) + V(J) ^ 2: NEXT J: B(14) = S / O(14)
2130 S = 0: O(15) = 0: FOR J = 1 TO X: S = S + I(J) * V(J) * Y(J)
2140 O(15) = O(15) + (I(J) * V(J)) ^ 2: NEXT J: B(15) = S / O(15): S = 0
2150 O(16) = 0: FOR J = 1 TO X: S = S + P(J) * V(J) * Y(J)
2160 O(16) = O(16) + (P(J) * V(J)) ^ 2: NEXT J: B(16) = S / O(16): S = 0
2170 O(17) = 0: FOR J = 1 TO X: S = S + U(J) * K(J) * Y(J)
2180 O(17) = O(17) + (U(J) * K(J)) ^ 2: NEXT J: B(17) = S / O(17): S = 0
2190 O(18) = 0: FOR J = 1 TO X: S = S + U(J) * Q(J) * Y(J)
2200 O(18) = O(18) + (U(J) * Q(J)) ^ 2: NEXT J: B(18) = S / O(18): S = 0
2210 O(19) = 0: FOR J = 1 TO X: S = S + I(J) * P(J) * V(J) * Y(J)
2220 O(19) = O(19) + (I(J) * P(J) * V(J)) ^ 2: NEXT J: B(19) = S / O(19)
2230 S = 0: O(20) = 0: FOR J = 1 TO X: S = S + I(J) * U(J) * Q(J) * Y(J)
2240 O(20) = O(20) + (I(J) * U(J) * Q(J)) ^ 2: NEXT J: B(20) = S / O(20)
2250 S = 0: O(21) = 0: FOR J = 1 TO X: S = S + P(J) * U(J) * K(J) * Y(J)
2260 O(21) = O(21) + (P(J) * U(J) * K(J)) ^ 2: NEXT J: B(21) = S / O(21)
2270 S = 0: O(22) = 0: FOR J = 1 TO X: S = S + K(J) * V(J) * Y(J)
2280 O(22) = O(22) + (K(J) * V(J)) ^ 2: NEXT J: B(22) = S / O(22)
2290 S = 0: O(23) = 0: FOR J = 1 TO X: S = S + Q(J) * V(J) * Y(J)
2300 O(23) = O(23) + (Q(J) * V(J)) ^ 2: NEXT J: B(23) = S / O(23)
2310 S = 0: O(24) = 0: FOR J = 1 TO X: S = S + I(J) * Q(J) * V(J) * Y(J)
2320 O(24) = O(24) + (I(J) * Q(J) * V(J)) ^ 2: NEXT J: B(24) = S / O(24)
2330 S = 0: O(25) = 0: FOR J = 1 TO X: S = S + P(J) * K(J) * V(J) * Y(J)
2340 O(25) = O(25) + (P(J) * K(J) * V(J)) ^ 2: NEXT J: B(25) = S / O(25)
2350 S = 0: O(26) = 0: FOR J = 1 TO X: S = S + U(J) * K(J) * Q(J) * Y(J)
2360 O(26) = O(26) + (U(J) * K(J) * Q(J)) ^ 2: NEXT J: B(26) = S / O(26)
2370 S = 0: O(27) = 0: FOR J = 1 TO X: S = S + K(J) * Q(J) * V(J) * Y(J)
2380 O(27) = O(27) + (K(J) * Q(J) * V(J)) ^ 2: NEXT J: B(27) = S / O(27): GOTO 2390
2390 PRINT #1, "B(J) ДО АНАЛИЗА": FOR J = 1 TO X
2395 PRINT #1, "B("; J; ")="; B(J)
2397 NEXT J: PRINT
2400 PRINT "ВВОД N0-КОЛИЧЕСТВО ОПЫТОВ НА СРЕДНЕМ УРОВНЕ ФАКТО-
РОВ"
2407 INPUT N0
2408 PRINT #1, "КОЛИЧЕСТВО ОПЫТОВ НА СРЕДНЕМ УРОВНЕ ФАКТОРОВ"
2410 PRINT #1, "N0="; N0
2415 IF X = 3 GOTO 2510




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