Синтез комбинационных схем. Довгий П.С - 51 стр.

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51
Продолжение приложения 1
1 2 3
112.
3|x
4
1x
5
- x
1
x
2
x
3
|<6
|x
4
1x
5
- x
1
x
2
x
3
|=0
113.
2|x
1
0x
5
-x
4
x
2
x
1
|
4
|x
1
0x
5
-x
4
x
2
x
1
|=0
114. 3<|x
2
1x
3
- x
4
x
1
x
3
|<6 |x
2
1x
3
- x
4
x
1
x
3
|=0
115.
1<|x
3
x
1
-x
2
x
4
x
5
|
4
| x
3
x
1
-x
2
x
4
x
5
|=7
116.
-2(x
4
x
5
-x
1
x
2
x
3
)<1
(x
4
x
5
-x
1
x
2
x
3
)=-5
117.
2|x
1
1x
5
-x
4
x
2
x
3
|
4
|x
1
1x
5
-x
4
x
2
x
3
|=6,7
118.
2|
x
2
x
1
0-x
3
x
4
x
5
|<5
|
x
2
x
1
0-x
3
x
4
x
5
|=1
119.
4<(x
1
x
2
+x
3
x
4
x
5
)
8
(x
3
x
4
x
5
)=2
120.
2|x
2
x
3
x
4
-x
5
x
1
|
5
(x
1
x
2
x
3
)=0
121.
-2(
x
1
x
2
0-x
3
x
4
x
5
)
1
(
x
1
x
2
0-x
3
x
4
x
5
)=-3
122. 1<|x
1
x
5
x
3
- x
4
1x
2
|<5 |x
1
x
5
x
3
- x
4
1x
2
|=7
123. (x
5
x
4
x
3
)
mod5
<x
1
x
2
(x
5
x
4
x
3
)=3
124.
3|x
4
1x
5
-x
1
x
2
x
3
|
5
|x
4
1x
5
-x
1
x
2
x
3
|=2
125.
8(x
5
x
2
x
4
+1x
1
x
3
)<12
(x
5
x
2
x
4
)=7
126. 1<|x
4
x
2
x
3
- x
1
1x
5
|<4 |x
4.
x
2
x
3
- x
1
1x
5
|=4
127.
3(x
1
x
2
x
3
+x
4
x
5
)
6
(x
1
x
2
x
3
+x
4
x
5
)=7
128. -3<(x
5
x
1
0-x
3
x
2
x
4
) <2 (x
5
x
1
0+x
3
x
2
x
4
)=2
129.
-2(x
1
x
2
-x
3
x
4
x
5
)
1
(x
1
x
2
-x
3
x
4
x
5
)=-3
130.
1|x
5
x
4
-x
2
x
3
x
1
|
2
| x
5
x
4
-x
2
x
3
x
1
|=3
131.
1<| x
4
x
2
x
1
-x
5
x
3
|
4
| x
4
x
2
x
1
-x
5
x
3
|=1
132.
5(x
4
x
5
+x
1
x
2
x
3
)
8
(x
1
x
2
x
3
)=1
133.
2|x
1
x
2
-x
3
x
4
x
5
|
4
|x
1
x
2
-x
3
x
4
x
5
|=5
134.
-2(x
2
x
3
0-x
4
x
5
x
1
)
1
(x
2
x
3
0-x
4
x
5
x
1
)=3
135. 7<(1x
1
x
5
+x
4
x
3
x
2
) <11 |x
1
x
2
x
3
-x
4
x
5
|=3
136. (x
3
x
2
+x
4
x
5
x
1
)=0, 5, 6, 7, 8 (x
4
x
5
x
1
)=2
137. (x
1
x
2
+x
3
x
4
x
5
)=1, 5, 6, 7, 8 (x
1
x
2
+x
3
x
4
x
5
)=3
138.
8(1x
3
x
2
+x
5
x
2
x
4
)
10
|x
5
x
1
x
2
-x
4
x
3
|=0
139.
2|x
3
0x
4
-x
5
x
1
x
2
|
4
|x
3
0x
4
-x
5
x
1
x
2
|=1
140.
1|x
3
x
2
x
1
-x
5
x
4
|
3
|x
3
x
2
x
1
-x
5
x
4
|=0