Стационарные машины и установки. Дроздова Л.Г. - 46 стр.

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46
;1260
94,01000
101088,11
4
2
кВтN =
⋅
⋅⋅
=
;626
94,01000
101088,5
4
43
кВтNN =
⋅
⋅⋅
==
;3,10
1000
94,010101,0
4
5
кВтN −=
⋅⋅⋅−
=
.0
6
=
N
3. Система с тяжелым уравновешивающим канатом (q – р = 9,43 -
8,37 = 1,06 кг/м) .
Движущие
усилия
по
формуле
(2.31)
в
точках
,
указанных
в
расчете
без
уравновешивающего
каната
:
(
)
[
]
(
)
;1012,11
75,00008081,906,173050002,1
4
11
H
amgpqHkQF
nn
⋅
=
⋅
+
⋅
⋅
−
⋅
=
+
−
−
=
(
)
(
)
[
]
(
)
[
]
;1026,1175,00008081,9
06,17,66273050002,12
4
112
H
amgpqhHkQF
nn
⋅=⋅+×
×
⋅
−
−
⋅
=
+
−
−
−
=
;1026,575,00008081,9
06,17,66273050002,12
4
13
H
gpqhHkQF
n
⋅=⋅+×
×
⋅
−
−
⋅
=
−
−
−
=
(
)
[
]
(
)
{
}
( )
[ ]
{ }
;105,681,906,16,5967,66273050002,1
2
4
214
H
gpqhhHkQF
n
⋅=⋅+−−⋅=
=
−
+
−
−
=
(
)
[
]
(
)
{
}
( )
[ ]
{ }
;105,0
75,00008081,906,16,5967,66273050002,1
2
4
3215
H
amgpqhhHkQF
nn
⋅=
=⋅−⋅+−−⋅=
=
−
−
+
−
−
=
(
)
[
]
(
)
.1064,0
75,00008081,906,173050002,1
4
36
H
amgpqHkQF
nn
⋅=
=
⋅
−
⋅
⋅
+
⋅
=
−
−
+
=
Мощности
на
валу
подъемного
двигателя
по
формуле
(2.37):
;0
1
=
N
;1198
94,01000
101026,11
4
2
кВтN =
⋅
⋅⋅
=
;560
94,01000
101026,5
4
3
кВтN =
⋅
⋅⋅
=
     11,88 ⋅ 10 4 ⋅ 10
N2 =                   = 1260 кВт ;
      1000 ⋅ 0,94
           5,88 ⋅ 10 4 ⋅ 10
N3 = N 4 =                  = 626 кВт ;
            1000 ⋅ 0,94
     − 0,1 ⋅ 10 4 ⋅ 10 ⋅ 0,94
N5 =                          = −10,3 кВт ;
             1000
N 6 = 0.
      3. Система с тяжелым уравновешивающим канатом (q – р = 9,43 -
8,37 = 1,06 кг/м) . Движущие усилия по формуле (2.31) в точках, указанных
в расчете без уравновешивающего каната:
F1 = [kQn − H (q − p )]g + mn a1 = (1,2 ⋅ 5000 − 730 ⋅ 1,06 ) ⋅ 9,81 + 80 000 ⋅ 0,75 =
11,12 ⋅ 10 4 H ;
F2 = [kQn − (H − 2h1 )(q − p )]g + mn a1 = [1,2 ⋅ 5000 − (730 − 2 ⋅ 66,7 )1,06]×
× 9,81 + 80 000 ⋅ 0,75 = 11,26 ⋅ 10 4 H ;
F3 = [kQn − (H − 2h1 )(q − p )]g = [1,2 ⋅ 5000 − (730 − 2 ⋅ 66,7 )1,06]×
× 9,81 + 80 000 ⋅ 0,75 = 5,26 ⋅ 10 4 H ;
F4 = { kQn − [ H − 2( h1 + h2 ) ]( q − p ) } g =
= {1,2 ⋅ 5000 − [ 730 − 2( 66,7 + 596,6 ) ]1,06 }⋅ 9,81 = 6,5 ⋅ 10 4 H ;
F5 = { kQn − [ H − 2( h1 + h2 ) ]( q − p ) } g − mn a3 =
= {1,2 ⋅ 5000 − [ 730 − 2( 66,7 + 596,6 ) ]1,06 }⋅ 9,81 − 80 000 ⋅ 0,75 =
= 0,5 ⋅ 10 4 H ;
F6 = [kQn + H (q − p )]g − mn a3 = (1,2 ⋅ 5000 + 730 ⋅ 1,06 ) ⋅ 9,81 − 80 000 ⋅ 0,75 =
= 0,64 ⋅ 10 4 H .

Мощности на валу подъемного двигателя по формуле (2.37):
  N1 = 0 ;
       11,26 ⋅ 10 4 ⋅ 10
  N2 =                   = 1198 кВт ;
         1000 ⋅ 0,94
       5,26 ⋅ 10 4 ⋅ 10
  N3 =                  = 560 кВт ;
        1000 ⋅ 0,94



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