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AND (city LIKE “[CPR]%” OR city LIKE “%San%”)
AND (title LIKE “% the %” OR title LIKE “The %”
OR title LIKE “% a %” OR title LIKE “A %”)
51) SELECT DISTINCT au_lname, au_fname
FROM authors a JOIN titleauthor ta ON a.au_id=ta.au_id
JOIN titles t ON ta.title_id=t.title_id
JOIN publishers p ON p.pub_id=t.pub_id
WHERE p.state= “CA”
ORDER BY au_lname, au_fname
52) SELECT pub_name
FROM publishers p JOIN titles t ON p.pub_id=t.pub_id
WHERE $15>price AND type= “psychology”
ORDER BY pub_name
53) SELECT pub_name, AVG(price)
FROM titles t, publishers p
WHERE t.pub_id=p.pub_id
GROUP BY pub_name
54) SELECT pub_name, AVG(price)
FROM titles t JOIN publishers p ON t.pub_id=p.pub_id
GROUP BY pub_name
55) SELECT au_lname, au_fname, title
FROM authors a, titles t, titleauthor ta
WHERE ta.title_id=t.title_id AND a.au_id=ta.au_id
AND type= “popular_comp”
56) SELECT au_lname, au_fname, title
FROM authors a JOIN titleauthor ta ON a.au_id=ta.au_id
JOIN titles t ON ta.title_id=t.title_id
WHERE type= “psychology”
57) SELECT au_lname, au_fname, pub_name, COUNT(*)
FROM authors a, titles t, titleauthor ta, publishers p
AND (city LIKE “[CPR]%” OR city LIKE “%San%”) AND (title LIKE “% the %” OR title LIKE “The %” OR title LIKE “% a %” OR title LIKE “A %”) 51) SELECT DISTINCT au_lname, au_fname FROM authors a JOIN titleauthor ta ON a.au_id=ta.au_id JOIN titles t ON ta.title_id=t.title_id JOIN publishers p ON p.pub_id=t.pub_id WHERE p.state= “CA” ORDER BY au_lname, au_fname 52) SELECT pub_name FROM publishers p JOIN titles t ON p.pub_id=t.pub_id WHERE $15>price AND type= “psychology” ORDER BY pub_name 53) SELECT pub_name, AVG(price) FROM titles t, publishers p WHERE t.pub_id=p.pub_id GROUP BY pub_name 54) SELECT pub_name, AVG(price) FROM titles t JOIN publishers p ON t.pub_id=p.pub_id GROUP BY pub_name 55) SELECT au_lname, au_fname, title FROM authors a, titles t, titleauthor ta WHERE ta.title_id=t.title_id AND a.au_id=ta.au_id AND type= “popular_comp” 56) SELECT au_lname, au_fname, title FROM authors a JOIN titleauthor ta ON a.au_id=ta.au_id JOIN titles t ON ta.title_id=t.title_id WHERE type= “psychology” 57) SELECT au_lname, au_fname, pub_name, COUNT(*) FROM authors a, titles t, titleauthor ta, publishers p 22
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