Элементы дискретной математики. Часть I - 130 стр.

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k
K
s+1
= K
s
∪ K
s
.
K
0
⊆ K
1
⊆ K
2
⊆ ...⊆ K
s
⊆ K
s+1
.
K
s+1
= K
s
K
s+2
= K
s+1
K
s+3
= K
s+2
K
0
⊆ K
1
⊆ K
2
⊆ ...⊆ K
s
⊆ ...
s
∗
≤ k
k
2
K
0
⊂ K
1
⊂ K
2
⊂ ...⊂ K
s
∗
= K
s
∗
+1
= K
s
∗
+2
= ....
K
s
∗
=[f
1
,...,f
m
]
x
1
,x
2
,
K K
x
1
,x
2
K x
1
x
2
V
x
1
,x
2
K
s
∗
K
s
∗
=[f
1
,...,f
m
]
x
1
,x
2
V
x
1
,x
2
[f
1
,...,f
m
] [f
1
,...,f
m
] = P
k
f
1
f
m
V
x
1
,x
2
K
s
∗
=[f
1
,...,f
m
]
x
1
,x
2
P
k
=[V
x
1
,x
2
] ⊆ K
s
∗
⊆ [f
1
,...,f
m
] ⊆ P
k
.
[f
1
,...,f
m
]=P
k
k f
1
f
m
K
K
m g(x
1
,...,x
m
)
K m f
1
(x
1
,...,x
n
) f
m
(x
1
,...,x
n
) K
g(f
1
(x
1
,...,x
n
),...,f
m
(x
1
,...,x
n
)) ∈ K.
K K
K K
I
m
t
(x
1
,...,x
m
) K
[K]=K
k

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