Элементы дискретной математики. Часть I - 30 стр.

UptoLike

C
0
(f)=1/2
n
·||f|| 0 C
0
(f) 1
a =0
1/2 C
a
(f) 1/2.
Σ
aE
n
2
C
a
(f)=f(0).
b E
n
2
Σ
aE
n
2
Z
a
(f) · Z
ab
(f)=0.
b =0
Σ
aE
n
2
(Z
a
(f))
2
=2
2n
.
Σ
aE
n
2
Z
a
(f) · Z
ab
(f)= Σ
aE
n
2
Σ
xE
n
2
(1)
f(x)
(1)
(a,x)
Σ
yE
n
2
(1)
f(y)
(1)
(ab,y)
=
yE
n
2
(1)
f(y)
(1)
(b,y)
Σ
xE
n
2
(1)
f(x)
Σ
aE
n
2
(1)
(a,x)
(1)
(a,y)
=
=2
n
Σ
yE
n
2
(1)
2f(y)
(1)
(b,y)
=2
n
Σ
yE
n
2
(1)
(b,y)
=2
2n
δ
b,0
.
F
E
n
2
F F F
E
n
2
V
n
F (n) F
V
n
F
F a V
n
e
a
(x)
e
a
(x)=
0,
x = a;
1,
x = a.
(e
a
(x))
aV
n
F (n) dim
F
F (n)=2
n