Алгоритмизация и имитационное моделирование с применением аппарата систем массового обслуживания. Финаев В.И. - 140 стр.

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140
Продолжение табл. 26
11
α
1
=0,3; α
2
=0,1;
α
3
=0,4; α
4
=0,1
b
1
=0,005;
b
2
=0,001;
b
3
=0,003;
b
4
=0,05
1
0
h
=0,92;
1
1
h
=0,08;
2
0
h =0,9;
2
1
h =0,1;
3
0
h =0,87;
3
1
h =0,13;
4
0
h =0,88;
4
1
h =0,12
12
α
1
=0,4; α
2
=0,1;
α
3
=0,05; α
4
=0,1
b
1
=0,05;
b
2
=0,01;
b
3
=0,03;
b
4
=0,05
1
0
h =0,9;
1
1
h =0,1;
2
0
h =0,7;
2
1
h =0,3;
3
0
h
=0,85;
3
1
h
=0,15;
4
0
h =0,9;
4
1
h =0,1
13
α
1
=0,05; α
2
=0,1;
α
3
=0,2; α
4
=0,1
b
1
=0,25;
b
2
=0,15;
b
3
=0,3;
b
4
=0,5
1
0
h =0,7;
1
1
h =0,3;
2
0
h =0,9;
2
1
h =0,1;
3
0
h =0,8;
3
1
h =0,2;
4
0
h =0,9;
4
1
h =0,1
14
α
1
=0,03; α
2
=0,08;
α
3
=0,1; α
4
=0,05
b
1
=1,5;
b
2
=1,0;
b
3
=0,5;
b
4
=2,0
1
0
h =0,85;
1
1
h =0,15;
2
0
h
=0,9;
2
1
h
=0,1;
3
0
h =0,8;
3
1
h =0,2;
4
0
h =0,7;
4
1
h =0,3
15
α
1
=1; α
2
=3;
α
3
=5; α
4
=2
b
1
=0,05;
b
2
=0,005;
b
3
=0,02;
b
4
=0,05
1
0
h =0,9;
1
1
h =0,1;
2
0
h =0,6;
2
1
h =0,4;
3
0
h =0,9;
3
1
h =0,1;
4
0
h
=0,85;
4
1
h
=0,15