# Английский язык. Ильичева Н.А - 10 стр.

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• ## Иностранный язык

10
= = 1.4 m/s
time 70 s
The 7) ……. of average velocity, on the other hand, was:
displacement 40 m
= = 0.57 m/s
time 70 m
16. Some given or known quantities in the following problem are
missing. Look at the problem and the solution, then fill in the gaps with
the words from the list to explain what numerical values in the equation
mean:
change in velocity, final velocity (2), slow down, initial velocity (2), average
acceleration.
An automobile is moving along a straight highway and the driver puts on
the brakes. What was the cars average acceleration?
Solution:
5.0 m/s 15.0 m/s
a = = - 2.0 m/s
2
5.0 s
a) 5.0 s - the time taken to ……
b) 15.0 m/s the cars ………
c) 5.0 m/s the cars ……
d) 5.0 m/s 15.0 m/s the ……..
e) 2.0 m/s
2
the cars ……… . The negative sign appears because the ………
is less than the ……… .
17. Johns father is trying to warn his son against speedy driving. Complete
their conversation with the words from the list:
calculate, multiply, conditions, stopping distance, application, decelerate, brake,
speed, increase.
F: Well John, you shouldnt drive your car at a a) ……. of 100 km/h in town.
Its too dangerous.
J: Dont worry, Dad. I never speed up in crowded places. But why not b) …….
speed when the streets become empty.
F: Dont you understand that you can meet with an unpredictable situation if
someone tries to run across the street right in front of your car?
J: If it happens, Ill just c) ……. .
F: Im afraid it is not as simple as that. You forget that the braking distance may
be quite long.
J: It cant be very long because my car is new. Its got good tires and good
brakes which can d) ……. at 6.0 m/s
2
(six meters per second).
                                        10

=                   = 1.4 m/s
time               70 s
The 7) ……. of average velocity, on the other hand, was:

displacement        40 m
=          = 0.57 m/s
time             70 m

16. Some “given” or “known” quantities in the following problem are
missing. Look at the problem and the solution, then fill in the gaps with
the words from the list to explain what numerical values in the equation
mean:
change in velocity, final velocity (2), slow down, initial velocity (2), average
acceleration.
An automobile is moving along a straight highway and the driver puts on
the brakes. What was the car’s average acceleration?
Solution:
5.0 m/s – 15.0 m/s
a=                     = - 2.0 m/s2
5.0 s
a) 5.0 s - the time taken to ………
b) 15.0 m/s – the car’s ………
c) 5.0 m/s – the car’s ………
d) 5.0 m/s – 15.0 m/s – the ……..
e) – 2.0 m/s2 – the car’s ……… . The negative sign appears because the ………
is less than the ……… .

17. John’s father is trying to warn his son against speedy driving. Complete
their conversation with the words from the list:
calculate, multiply, conditions, stopping distance, application, decelerate, brake,
speed, increase.
F: Well John, you shouldn’t drive your car at a a) ……. of 100 km/h in town.
It’s too dangerous.
J: Don’t worry, Dad. I never speed up in crowded places. But why not b) …….
speed when the streets become empty.
F: Don’t you understand that you can meet with an unpredictable situation if
someone tries to run across the street right in front of your car?
J: If it happens, I’ll just c) ……. .
F: I’m afraid it is not as simple as that. You forget that the braking distance may
be quite long.
J: It can’t be very long because my car is new. It’s got good tires and good
brakes which can d) ……. at 6.0 m/s2 (six meters per second).