Декодирование циклических кодов: Руководство к лабораторной работе. Кавчук С.В. - 24 стр.

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ПРИЛОЖЕНИЕ
Варианты домашнего задания
варианта
Вид кода
(n,m)
Образующий полином Двучлен
x
n
+1
1
2
3
4
5
6
7
8
9
10
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n=6, m=3
n=7, m=4
n=7, m=4
n=10, m=6
n=12, m=6
n=12, m=8
n=14, m=8
n=15, m=9
n=15, m=9
n=15, m=9
n=15, m=11
n=15, m=11
n=21, m=16
n=21, m=16
n=21, m=15
n=21, m=15
n=7, m=3
n=15, m=10
n=15, m=10
n=15, m=9
n=21, m=15
n=21, m=15
n=21, m=12
n=21, m=12
n=21, m=12
n=14, m=7
n=12, m=5
n=15, m=8
n=15, m=8
n=15, m=8
P(x)=x
3
+x+1
P(x)=x
3
+x+1
P(x)=x
3
+x
2
+1
P(x)=x
4
+x
3
+1
P(x)=x
6
+x
5
+x
3
+x+1
P(x)=x
4
+x+1
P(x)=x
6
+x
4
+1
P(x)=x
6
+x
4
+x
3
+x
2
+1
P(x)=x
6
+x
3
+x2+x+1
P(x)=x
6
+x
5
+x4+x3+1
P(x)=x
4
+x+1
P(x)=x
4
+x
3
+1
P(x)=x
5
+x
4
+1
P(x)=x
5
+x+1
P(x)=x
6
+x
4
+x
2
+x+1
P(x)=x
6
+x
5
+x
4
+x
2
+1
P(x)=x
4
+x
2
+x+1
P(x)=x
5
+x
4
+x
2
+1
P(x)=x
5
+x
3
+x+1
P(x)=x
6
+x
4
+x
2
+x+1
P(x)=x
6
+x
5
+x
2
+1
P(x)=x
6
+x
4
+x+1
P(x)=x
9
+x
8
+x
7
+x
6
+1
P(x)=x
9
+x
7
+x
6
+x
5
+x
3
+x
2
+x+1
P(x)=x
9
+x
8
+x
7
+x
6
+x
4
+x
3
+x
2
+1
P(x)=x
7
+x
6
+x
4
+x
4
+x+1
P(x)=x
7
+x
5
+x
4
+x
3
+1
P(x)=x
7
+x
6
+x
5
+x
2
+x+1
P(x)=x
7
+x
6
+x
4
+1
P(x)=x
7
+x
3
+x+1
x
7
+1
x
7
+1
x
7
+1
x
15
+1
x
12
+1
x
15
+1
x
14
+1
x
15
+1
x
15
+1
x
15
+1
x
15
+1
x
15
+1
x
21
+1
x
21
+1
x
21
+1
x
21
+1
x
7
+1
x
15
+1
x
15
+1
x
21
+1
x
21
+1
x
21
+1
x
21
+1
x
21
+1
x
21
+1
x
14
+1
x
12
+1
x
15
+1
x
15
+1
x
15
+1