Анализ графов на ЭВМ. Макарычев П.П - 32 стр.

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32
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b"ðįð… ,ðććććććććććććććććć..ćććććććć......................................................................................
................................ 3
k=K%!=2%!…= !=K%2= 1 1. l=2!,Ķ…/ ð C!ðį“2=" ð… ,
, .=!=*2ð!,“2,*, Į!=- %"ćććććććććććććććććć...ććććć..............
............................................................................ 4
k=K%!=2%!…= !=K%2= 1 2. r…=!…/ ð , K ,
…=!…/ ð %Cð!=İ,, … =į Į!=- =Ą,ć............. 8
k=K%!=2%!…= !=K%2= 1 3. ` …= ,ƒ “"%L“2" “ð2ðL o ð2!,ć..ććć..............................
.........12
k=K%!=2%!…= !=K%2= 1 4 . bð!ķ ,……= , !ðKð!…= …ðƒ=",“,Ą%“2, ćć.......................16
k=K%!=2%!…= !=K%2= 1 5 . bð!ķ ,……= , !ðKð!…= “" ƒ…%“2Ĺ Į!=- %"ć.ć..
................18
k=K%!=2%!…= !=K%2= 1 6 . b…ðķ … 3“2%LĶ,"%“2Ĺ , C%*!/2, " Į!=- =.ćććććććććććććććććććććććććć.............21
k=K%!=2%!…= !=K%2= 1 7 . 0 ðC, , İ,* / " Į!=- =.ććć.....
............................................24
q C,“%* ,2ð!=23!/ ..............................................
........................................................ćććććććććććććććććććććć27
o !, %› ð…,ðććććććććććććććććććććććć...................................
...............................................................................28
` …= ,ƒ Į!=- %" …= } bl
l ð2%į,Ķð“*,ð 3*=ƒ=…,
* "/C% …ð…,ĺ =K%!=2%!…/ . ! =K%2
pðį=*2%! b. b. ) 3"=ķ %"=
Šð.…,Ķð“*,L !ðį=*2%! m . ` . b Ĺ *%"=
j %!!ð*2%! m . ` . q ,įð Ĺ…,
*%"=
j%Ą CĹĺ 2ð!… = "ð!“2*= m . b. h "=…%"%L
hd 1 06494 %2 26.12.01
q į=…% " C!%,ƒ"%į“2"% 10.03.05. t %!Ą =2 6 0x84
1
/16.
a 3Ą =Į= Į=ƒð2…= . o ðĶ=2Ĺ % -“ð2…= . r“ . CðĶ. . 1,86.
r Ķ.-, ƒį. . 2,22. Š ,!=› 100. g=*=ƒ 1 138. œq B 21.
_______________________________________________________
h ƒį=2ð Ĺ“2"% o ð… ƒð… “*%Į% Į
%“3į=!“2"ð……%Į% 3…,"ð!“, 2ð2=.
440026, o ð… ƒ=, j!=“…= , 4 0. 
                                                      q n d e pf ` m h e
b "ðįð…,ðć
         ..ć
         ć ...................................................................................................................... 3
k =K%!=2%!…= !=K%2= 1 1. l =2!,Ķ…/ ð C!ðį“2=" ð…,
, .=!=*2ð!,“2,*, Į!=- %"ć
                        ...ć
                        ć  .......................................................................................... 4
k =K%!=2%!…= !=K%2= 1 2. r …=!…/ ð , K,…=!…/ ð %Cð!=İ,, …=į Į!=- =Ą ,ć
                                                                     ............. 8
k =K%!=2%!…= !=K%2= 1 3. ` …= ,ƒ “"%L“2" “ð2ðL o ð2!,ć .......................................12
                                                     ..ć
k =K%!=2%!…= !=K%2= 1 4. b ð!ķ ,……= , !ðKð!…= …ðƒ=",“,Ą %“2,ć
                                                            ć
                                                            .......................16
                                                               .ć..................18
k =K%!=2%!…= !=K%2= 1 5. b ð!ķ ,……= , !ðKð!…= “" ƒ…%“2Ĺ Į!=- %"ć
k =K%!=2%!…= !=K%2= 1 6. b …ðķ …                           3“2%LĶ,"%“2Ĺ , C%*!/ 2, " Į!=- =.ć
                                                                                            .............21
                                                                                            ć
                                                .................................................24
k =K%!=2%!…= !=K%2= 1 7. 0 ðC, , İ,* / " Į!=- =.ć
                                                ć
q C,“%* ,2ð!=23!/ ......................................................................................................ć
                                                                                                                        27
                                                                                                                        ć
            ć..................................................................................................................28
o !, %› ð…,ðć




                                           ` …= ,ƒ Į!=- %" …= } b l

                                             l ð2%į,Ķð“*,ð 3*=ƒ=…,
                                       * "/ C% …ð…,ĺ =K%!=2%!…/ . !=K%2




                                            pðį=*2%! b. b. ) 3"=ķ %"=
                                    Šð.…,Ķð“*,L !ðį=*2%! m . ` . bĹ *%"=
                                         j %!!ð*2%! m . ` . q ,įð Ĺ…,*%"=
                                    j %Ą CĹĺ 2ð!…= "ð!“2*= m . b. h "=…%"%L


                                      h d 1 06494 %2 26.12.01
                        q į=…% " C!%,ƒ"%į“2"% 10.03.05. t %!Ą =2 60x841/16.
                      a 3Ą =Į= Į=ƒð2…= . o ðĶ=2Ĺ %- “ð2…= . r “ . CðĶ. . 1,86.
                        r Ķ.-,ƒį. . 2,22. Š,!=› 100. g=*=ƒ 1 138. œq B 21.
               _______________________________________________________
                  h ƒį=2ð Ĺ“2"% o ð…ƒð…“*%Į% Į%“3į=!“2"ð……%Į% 3…,"ð!“,2ð2=.
                                    440026, o ð…ƒ=, j !=“…= , 40.




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