Задачи по аналитической геометрии. Микенберг М.А. - 19 стр.

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ax+by+c = 0 (a; b)
d (x
0
; y
0
) ax + by + c = 0
d =
| ax
0
+ by
0
+ c |
a
2
+ b
2
.
ϕ
~a
~
b
cos(ϕ) =
|(~a,
~
b)|
|~a||
~
b|
.
k ax + by + c = 0
k = a/b
(2; 1) 3x + 4y + 7 = 0
3x 4y 10 = 0
6x 8y + 5 = 0
3x4y 10 = 0
d = 3
5x 12y 65 = 0 5x
12y + 26 = 0
3x4y12 =
0
(2; 5)
x 2y 7 = 0
5x 2y 1 = 0
5x 2y + 7 = 0 5x 2y 9 = 0
10x + 15y 3 = 0 2x + 3y + 5 = 0 2x + 3y 9 = 0