Задачи по аналитической геометрии. Микенберг М.А. - 42 стр.

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Составители: 

2x y + cz 2 = 0
x = 1 + 2t,
y = 2 3t,
z = 3 + 2t
(2; 2; 1)
x 2
3
=
y + 1
2
=
z 3
2
x 1
3
=
y 2
2
=
z + 3
2
.
(3; 2; 4) 3x2y 3z 7 = 0
x 2
3
=
y + 4
2
=
z 1
2
.
3x + 12y 3z 5 = 0 3x 4y + 9z + 7 = 0
x + 5
2
=
y 3
4
=
z + 1
3
x 3
2
=
y + 1
3
=
z 2
4
.
a d
2x + y z + 3 = 0 x 3y + 5 = 0 ax + y 2z + d = 0
3x 4y + 5 = 0 x 2z + 1 = 0 2y 3z 1 = 0
x + y z + 2 = 0 4x 3y + z 1 = 0 2x + y 5 = 0
OX
XOZ
(1; 3; 2)