Задачи по аналитической геометрии. Микенберг М.А. - 46 стр.

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x + 2y + 3z 5 = 0
½
5x 4y 2z 5 = 0,
x + 2z 2 = 0
2x y + z 1 = 0
A(3; 1; 1) B(1; 2; 7)
C(5; 14; 3)
B
A(2; 1; 3) B(5; 2; 7)
C(7; 11; 6)
A
A(1; 2; 4) B(3; 1; 3)
C(5; 1; 7)
B
1)
x
1
=
y 1
2
=
z
3
½
3x + y 5z + 1 = 0,
2x + 3y 8z + 3 = 0;
2)
x = 1 + 2t,
y = 2 + 3t,
z = 1 6t
½
2x + y 4z + 2 = 0,
4x y 5z + 4 = 0;
3)
½
x + y 3z 1 = 0,
2x y 9z 2 = 0
½
2x + y + 2z + 5 = 0,
2x 2y z + 2 = 0.
x 3
1
=
y + 2
1
=
z
2
x + 2
1
=
y 3
1
=
z + 5
2
.
½
x y 4z 5 = 0,
2x + y 2z 4 = 0
½
x 6y 6z + 2 = 0,
2x + 2y + 9z 1 = 0.
A(2; 3; 5) 6x 3y 5z + 2 = 0