Задачи по аналитической геометрии. Микенберг М.А. - 49 стр.

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A(1; 1; 1) B(2; 1; 3) C(4; 5; 2)
x 2y 2z 12 = 0 x 2y 2z 6 = 0
2x 3y + 6z 14 = 0 4x 6y + 12z + 21 = 0
2x y + 2z + 9 = 0 4x 2y + 4z 21 = 0
2x 2y + z 1 = 0 2x 2y +
z + 5 = 0
OY x + 2y 2z 2 = 0
d = 4
OZ (1; 2; 0)
3x 2y + 6z 9 = 0
2x y + 2z 3 = 0 3x + 2y 6z 1 = 0
(1; 2; 3)
2x 3y 4z 3 = 0 4x 3y 2z 3 = 0
3x 4y z + 5 = 0 4x 3y + z + 5 = 0
α(x 3y + 7z + 36) + β(2 x + y z 15) = 0
d = 3
α(10x 8y 15z + 56) + β(4x + y + 3 z 1) = 0
(3; 2; 3) d = 7
α(4x + 13y 2z 60) + β(4x + 3y + 3z 30) = 0
XOY
6
(2; 1; 3)
x = 3t,
y = 7 + 5t,
z = 2 + 2t.