Задачи по аналитической геометрии. Микенберг М.А. - 70 стр.

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(2; 1; 0)
¡
4
3
; 0;
1
3
¢
(0; 2; 1)
d = 4 d = 9 d = 3
l = 3
x+4
3
=
y+5
2
=
z3
1
5x + 5z 8 = 0
l = 5 m = 11
l 6= 7 l = 7 m = 3 l = 7 m 6= 3
(2; 3; 6)
x2
2
=
y+4
5
=
z+1
3
c = 2
4x + 6y + 5z 1 = 0
6x 20y 11z + 1 = 0
x3
5
=
y+2
6
=
z+4
9
x = 3 + 8t y = 1 3t z = 2 4t
a =
13
3
d =
23
3
x 2y + 3z + 3 = 0
x y 3z + 2 = 0
(3; 5; 1) (1; 7; 9) (0; 1; 13)
7x y 5z = 0
4x y 2z 9 = 0
60
45
60
120
60
45
11x 2y 15z 3 = 0
4x + 3y 5 = 0 5x + 3z 7 = 0 5x 4y + 1 = 0
x 8y + 5z 3 = 0
x 1 =
y2
3
=
x+7
8
x2
6
=
y+1
1
=
x+3
7
x = 3 + 3t y = 1 + 15t z = 3 + 19t
60