История метрологии, стандартизации, сертификации и управления качеством. Мищенко С.В - 53 стр.

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9
Y =
0,5/[(A+B)(C–
D)
⋅
E
2
]
10
Y = A
⋅
(B+C–
D)/[3
⋅
E
3
]
11
Y = 3
⋅
A
⋅
B
2
/(C–
D+E)
12
Y = A
3
⋅
B/[3
⋅
(C–
D)
⋅
E]
13
Y =
2
⋅
A
⋅
B
3
/[(C+D–
E)]
14
Y = 3(A–
B)
⋅
C
2
/[2
⋅
(D+E)]
15
Y = 1/[A
⋅
(B–
C)
⋅
D
2
⋅
E]
∆
A =
1
A =
100
∆
B =
2
B =
80
∆
C = 1
C = 60
∆
D =
2
D =
40
∆
E =
1
E =
20
16
Y = (A–B–
C)
⋅
D
2
/[2
⋅
E]
17
Y =
0,4
⋅
A/[B
2
⋅
(C–
D)
⋅
E
3
]
18
Y =
A
2
⋅
(B+C)/[0,5(D
–E)]
19
Y = A
3
⋅
(B–
C)
⋅
(D+E)/2
20
Y =
(A+B)
⋅
C
2
⋅
(D–
E)/3
∆
A =
5
A =
200
∆
B =
3
B =
90
∆
C = 2
C = 70
∆
D =
2
D =
60
∆
E =
1
E =
30
21
Y =
4
⋅
A
⋅
B
2
⋅
C
3
/(D–E)
22
Y =
2/[(A+B)
⋅
C
3
(D–
E)]
23
Y = (A–
B)/[3(C+D)
⋅
E
2
]
24
Y = 0,1
⋅
(A–
B+C)/[D
3
⋅
E]
25
Y =
2
⋅
A/[(3
⋅
B
⋅
C
2
⋅
(D
–E)]
∆
A
=
0,5
A =
40
∆
B =
1
B =
30
∆
C =
0,5
C = 50
∆
D =
1,4
D =
70
∆
E =
2
E =
60
Продолжение табл. 6.4
ПОГРЕШНОСТИ И РЕЗУЛЬТА-
ТЫ ПРЯМЫХ ИЗМЕРЕНИЙ
№
ВАР
ИАН-
ТА
РАСЧЕТНАЯ
ЗАВИСИ-
МОСТЬ
A B C D E
26
Y = 3
⋅
A
2
/[(B–
C)
⋅
(D+E)]
∆
A =
3
∆
B =
2
∆
C = 1
C = 60
∆
D =
2
∆
E =
1

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