Квантовая механика. Мокшин А.В - 31 стр.

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υ = 2π¯h/mλ = 0.7 · 10
7
2.06 4.58
10
6
λ
0
=
2π¯hc
A
·
n − η
n − 1
= 0.26
φ = (¯hω − A)/e = 8
λ = [4πΛ/η − 1][sin
2
(θ
2
/2) − η sin
2
(θ
1
/2)] = 1.2
1.85
|p | = 2m
√
¯hω − E |p | = ¯hω/c
| | =
1
2
q
(¯hω)
2
+ 2mc
2
(¯hω − E) = 95.5
/c c
T = ¯hω
0
− E = pc/[1 − 2(pc/mc
2
) sin
2
θ/2] = 0.2
T = E
0
−E = ¯h(ω
0
−ω) ω
0
ω
T sin
2
θ/2 = 1
∆λ =
4π¯h
mc
T
max
=
8π
2
h
2
mλλ
0
λ = Λ(
p
1 + 2mc
2
/T
max
− 1) = 0.02 A
T = Eη/(1 + η) = 0.2
                                                    A!


                            4 $,&.21 9. /&(2$"B #1 :24 J!1 5 :26;1 :2# 5 6


                                              !5
            υ = 2πh̄/mλ = 0.7 · 107                ?
   @
            2.06
                    6     4.58
                                    5
   N             !5
            106     ?
   Q             2πh̄c n − η                        &35
            λ0 =         ·      = 0.26
                     A     n−1
  
            φ = (h̄ω − A)/e = 8
                                           5
  
            λ = [4πΛ/η − 1][sin2 (θ2 /2) − η sin2 (θ1 /2)] = 1.2
                                                                                   85
               O, 5
            1.85
                 √
            |p | = 2m h̄ω − E
                              %                 |p# | = h̄ω/c
                                                                  5
              7  !    -,!      8 -  < !
                     1
                        q
                              2                                                  %&7   0!     !  <
            | | = 2 (h̄ω) + 2mc2 (h̄ω − E) = 95.5                             /c           c
            !  5
                                                                                  O, 5
            T = h̄ω 0 − E = pc/[1 − 2(pc/mc2 ) sin2 θ/2] = 0.2
        




           !  +   7  0        8         ! 0  23 9  
            T = E 0 −E = h̄(ω 0 −ω)
                                        % 7   ω0  ω !   2B# &-   "  8    5
            P    %   T . -     !   < 8   sin2 θ/2 = 1 %  5  5 8  
                    4πh̄ %            8π 2 h2 5
            ∆λ =            T     =max
                       mc          mλλ0
            P !   * λ = Λ(p1 + 2mc2 /T − 1) = 0.02 A 5
                                          max
  @
            T = Eη/(1 + η) = 0.2
                                                O, 5



                                                            TD

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