Методы анализа сложных сигналов. Павлов А.Н. - 24 стр.

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z(t)
Z(f) = X(f) + j
b
X(f) =
2X(f), f > 0,
0, f < 0,
X(0), f = 0.
x(i) = x(it), i = 1, . . . , N X(f
k
)
N 6= 2
j
Z(f
k
)
Z(f
k
)
z(i)
z(i)
bx(i) = Im [z(i)]
x(t) y(t)
X(f) Y (f) bx(t) = H[x(t)] by(t) = H[y(t)]
H[ax(t) + by(t)] = abx(t) + bby(t)
H[x(t a)] = bx(t a).
x(t)
bx(t)
x(t)
H[bx(t)] = x(t).
H
1
x(t) = H
1
[bx(τ)] =
1
π
Z
−∞
bx(τ)
t τ
.