Методические указания к курсовой работе по дисциплине "Переходные процессы". Пилипенко В.Т. - 16 стр.

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;451.1
121
1000
2
12534.0
2
22
201
22*
0
21*
0
=⋅
⋅
=⋅
⋅
==
Б
Б
U
S
lX
XX
.322.2
121
1000
10034.0
22
401
24*
0
23*
0
=⋅⋅=⋅==
Б
Б
U
S
lXXX
3.1.1.5 Определение сопротивлений генераторов станций и питающей
системы
- Станция №1:
.808.0683.7
121
75.15
200
85.01000
19.0
2
2
2
1
2
``
30*
0
29*
0
=⋅
⋅
⋅
⋅=⋅
⋅⋅== k
U
U
S
S
XXX
Б
Н
Н
Б
d
- Станция №2:
;
2
2
2
``
11*
0
9*
0
7*
0
5*
0
3*
0
1*
0
k
U
U
S
S
XXXXXXX
Б
Н
Н
Б
d
⋅
⋅⋅======
.553.005.6
121
20
300
85.01000
195.0
2
2
11*
0
9*
0
7*
0
5*
0
3*
0
1*
0
=⋅
⋅
⋅
⋅====== XXXXXX
- Станция №3:
;
2
3
2
``
38*
0
36*
0
34*
0
32*
0
k
U
U
S
S
XXXXX
Б
Н
Н
Б
d
⋅
⋅⋅====
.158.1768.8
121
8.13
115
9.01000
148.0
2
2
38*
0
36*
0
34*
0
32*
0
=⋅
⋅
⋅
⋅==== XXXX
- Система:
.36.0348.0
121
330
2500
1000
2
2
2
5
2
13*
0
=⋅
⋅=⋅
⋅= k
U
U
S
S
X
Б
Н
К
Б
3.1.1.6 Определение сопротивления реактора
.164.1683.7
121
10
6.1
771.4
100
8
%100
%
22
1
28*
0
=⋅⋅⋅=⋅⋅⋅= k
U
U
I
IX
X
Б
Н
Н
БL
3.1.1.7 Определение ЭДС источников
;13.105.6
121
20
13.1
2
``
6
``
5
``
4
``
3
``
2
``
1
=⋅⋅=⋅⋅====== k
U
U
EEEEEEE
Б
HG
G
;949.0348.0
121
330
1
5
``
7
=⋅⋅=⋅⋅= k
U
U
EE
Б
HGS
G
16 
0             0        X 01 ⋅ l 2 S Б 0.34 ⋅ 125 1000
X *21 = X *22 =                  ⋅ 2 =               ⋅    2
                                                            = 1.451;
                          2       UБ          2        121
0             0                  S                  1000
X *23 = X *24        = X 01 ⋅ l 4 Б2 = 0.34 ⋅ 100 ⋅        = 2.322.
                                 UБ                 1212

     3.1.1.5 Определение сопротивлений генераторов станций и питающей
системы

        - Станция №1:
                                                  2                                                            2
0             0    SБ                     U                      1000 ⋅ 0.85  15.75 
X *29   = X *30 =        X d`` ⋅       ⋅  Н     ⋅ k12 = 0.19 ⋅            ⋅                2
                                                                                        ⋅ 7.683 = 0.808.
                   SН                     UБ                        200       121 
        - Станция №2:
                                                                                                  2
0         0          0             0       0          0                        SБ       U       
X *1 = X *3 = X *5 = X *7 = X *9 = X *11 =                           X d`` ⋅         ⋅  Н       ⋅ k 22 ;
                                                                               SН       UБ       
                                                                                                               2
0         0          0             0       0          0                   1000 ⋅ 0.85  20         2
X *1 = X *3 = X *5 = X *7 = X *9 = X *11                        = 0.195 ⋅            ⋅      ⋅ 6.05 = 0.553.
                                                                             300       121 
        - Станция №3:
                                                                                2
0             0          0             0                   SБ      U          
X *32 = X *34 = X *36 = X *38 =                  X d`` ⋅        ⋅  Н          ⋅ k 32 ;
                                                           SН      UБ          
                                                                                             2
0             0          0             0                 1000 ⋅ 0.9  13.8         2
X *32 = X *34 = X *36 = X *38                  = 0.148 ⋅           ⋅       ⋅ 8.768 = 1.158.
                                                           115       121 
        - Система:
                              2                                  2
0        S            U                1000  330 
X *13   = Б        ⋅  Н     ⋅ k 52 =     ⋅              2
                                                     ⋅ 0.348 = 0.36.
         SК           UБ               2500  121 

        3.1.1.6 Определение сопротивления реактора

0         X L% IБ UН 2         8 4.771 10
X *28 =       ⋅   ⋅    ⋅ k1 =    ⋅    ⋅   ⋅ 7.6832 = 1.164.
          100% I Н U Б        100 1.6 121

        3.1.1.7 Определение ЭДС источников

                                                                U HG                 20
E1`` = E 2`` = E3`` = E 4`` = E5`` = E6`` = EG ⋅                     ⋅ k 2 = 1.13 ⋅     ⋅ 6.05 = 1.13;
                                                                UБ                  121
                  U HGS            330
E7`` = EG ⋅             ⋅ k5 = 1 ⋅     ⋅ 0.348 = 0.949;
                   UБ              121


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