Методы нелинейной динамики. Постнов Д.Э - 72 стр.

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2 f(ν, z
n
)
1 f
(2)
(ν, z
n
)
x
1
z
1
= (
p
ν
2
+ 4ν ν)/2(ν + 3).
z
1
˜z = z z
1
˜z = 0 f(ν, ˜z) =
= f
(2)
(ν, z) z
1
z = ˜z + z
1
z
1
f(ν, ˜z) = c
1
˜z + c
2
˜z
2
+ ...,
˜z
n+1
= c
1
˜z
n
+ c
2
˜z
2
n
+ ...,
c
1
c
2
ν
z = a˜z
z
n+1
= c
1
z
n
+
c
2
a
z
2
n
+ ...
ν
c
1
= (ν + 1),
c
2
a
= (ν + 3).
ν a
ν
ν = ν
2
+ 4ν 2,
a =
ν
3
+ 7ν
2
+ 3
ν
2
+ 4ν(ν + 3) + 12ν
ν
2
+ 4ν + 1
.
z
ν
ν
a
ν
= ν
2
+ 4ν
2 ν
= 0.5615528...