Химическая кинетика (задачи, примеры, задания). Пурмаль А.П - 155 стр.

UptoLike

ВУЗ: 

МФТИ | Москва

Составители: 

Рубрика: 

155
CH
3
F C
3v
∠HCH = 110
o
r
C-H
=1,106
r
C-F
=1,385
ν
1
=3046
ν
2
=1496
ν
3
=1077
ν
4
=3165(2)
ν
5
=1514(2)
ν
6
=1207(2)
−238 ± 8
CH
2
OH
∠HCO = 116,4
o
∠COH = 109,0
o
r
C-H
=1,11
r
C-O
=1,34
r
O-H
=1,04
ν
CO
=1183,5
ν
крутильн.
=482
−33 ± 12
CH
3
I C
3v
∠HCH = 111
o
17′
r
C-H
=1,085
r
C-I
=2,133
ν
1
=2915
ν
2
=1251
ν
3
=533
ν
4
=3062(2)
ν
5
=1438(2)
ν
6
=883(2)
14,6 ± 1
CH
2
O
2
C
s
∠OCO = 125
o
∠H-C=O = 124
o
35′
∠C-O-H = 106
o
50′
r
C-H
=1,097
r
C=O
=1,228
r
C-O
=1,317
r
O-H
=0,974
r
O
…
O
=2,258
Цис транс
ν
1
3570 ν
1
3570
ν
2
2943 ν
2
2943
ν
3
1770 ν
3
1770
ν
4
1387 ν
4
1387
ν
5
1227 ν
5
1229
ν
6
1105 ν
6
1105
ν
7
625 ν
7
638
ν
8
1033 ν
8
1033
ν
9
638 ν
9
582
−379
CHCl
3
C
3v
∠ClCCl = 111
o
18′
∠HCCl = 107
o
34′
r
C-H
=1,100
r
C-Cl
=1,758
ν
1
=3034
ν
2
=680
ν
3
=363
ν
4
=1220(2)
ν
5
=774(2)
ν
6
=261(2)
−103,2 ± 1 
CH3F           C3v                  ν1=3046       −238 ± 8
          ∠HCH = 110o               ν2=1496
           rC-H=1,106               ν3=1077
           rC-F=1,385             ν4=3165(2)
                                  ν5=1514(2)
                                  ν6=1207(2)
CH2OH   ∠HCO = 116,4o             νCO=1183,5      −33 ± 12
        ∠COH = 109,0o            νкрутильн.=482
           rC-H=1,11
           rC-O=1,34
           rO-H=1,04
CH3I           C3v                 ν1=2915         14,6 ± 1
        ∠HCH = 111o17′             ν2=1251
          rC-H=1,085                ν3=533
          rC-I=2,133             ν4=3062(2)
                                 ν5=1438(2)
                                  ν6=883(2)


CH2O2           Cs           Цис         транс      −379
         ∠OCO = 125o         ν1 3570    ν1 3570
        ∠H-C=O = 124o35′     ν2 2943    ν2 2943
        ∠C-O-H = 106o50′     ν3 1770    ν3 1770
            rC-H=1,097       ν4 1387    ν4 1387
           rC=O=1,228        ν5 1227    ν5 1229
            rC-O=1,317       ν6 1105    ν6 1105
            rO-H=0,974       ν7 625     ν7 638
           rO…O=2,258        ν8 1033    ν8 1033
                             ν9 638     ν9 582
CHCl3          C3v                 ν1=3034        −103,2 ± 1
        ∠ClCCl = 111o18′            ν2=680
        ∠HCCl = 107o34′             ν3=363
           rC-H=1,100            ν4=1220(2)
          rC-Cl=1,758             ν5=774(2)
                                  ν6=261(2)


                           155

Страницы