Практикум по методам оптимизации. Семушин И.В. - 116 стр.

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d
0
T
1 0 1 1/2
1 2 3 4
=
σ
T
0 0 3/2
5 6 7
G
2 2 0 0
2 3 1 0
2 6 0 1
+
d
T
4 9 1 1
c
0T
1/3 0 0 2/3
1 2 3 4
=
π
T
0 0 2/3
5 6 7
G
2 2 0 0
2 3 1 0
2 6 0 1
+
c
T
1 4 0 0
(d
0
T
, σ
T
) NF = (1, 7, 3, 4),
l =
1, s = 1, d
0
s
= 1. NF (c
0T
, π
T
) s = 1
c
0
s
= 1/3.
a
0
s
= B
1
a
s
= 1 0 1/3
0 1 1/2
0 0 1/6
2
2
2
=
4/3
1
1/3
; b
0
=
4
3/2
3/2
min
4
4/3
,
3/2
1
,
3/2
1/3
k = 2, a
0
ks
= 1.
NB
5
1
2
NF
6
7
3
4
b
+
2
3/2
1
z
+
= z c
0
s
b
+
k
= 11/2
w
+
= w d
0
s
b
+
k
= 0
w := w
+
= 0
= (3/2, 1, 0, 0, 2, 0, 0) = , z = 11/2.