Практикум по методам оптимизации. Компьютерный курс. Семушин И.В. - 100 стр.

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min
µ
4
4/3
,
3/2
1
,
3/2
1/3
k = 2, a
0
ks
= 1.
3
.
NB
5
1
2
NF
6
7
3
4
b
+
2
3/2
1
z
+
= z c
0
s
b
+
k
= 11/2
w
+
= w d
0
s
b
+
k
= 0
w := w
+
= 0
= (3/2, 1, 0, 0, 2, 0, 0) = , z = 11/2.
B
1
1 4/3 1/3
0 1 1/2
0 1/3 1/3
π
+
T
0 1/3 5/6
=
π
T
0 0 2/3
β
T
k
0 1 1/2
·
c
0
s
1/3
σ
+T
0 1 1
=
σ
T
0 0 3/2
β
T
k
0 1 1/2
·
d
0
s
1
B
1
1 4/3 1/3
0 1 1/2
0 1/3 1/3
·
B
1 2 2
0 2 3
0 2 6
=
I
1 0 0
0 1 0
0 0 1
B
NB
NB = (5, 1, 2)
1
.
d
0T
0 0 0 0
1 2 3 4
=
σ
T
0 1 1
5 6 7
G
2 2 0 0
2 3 1 0
2 6 0 1
+
d
T
4 9 1 1
c
0T
0 0 1/3 5/6
1 2 3 4
=
π
T
0 1/3 5/6
5 6 7
G
2 2 0 0
2 3 1 0
2 6 0 1
+
c
T
1 4 0 0