Практикум по методам оптимизации. Компьютерный курс. Семушин И.В. - 119 стр.

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00
1
. k = 2.
2
. min
³
4/3
|−1|
,
5/3
|−1|
´
= 4/3 l = 2, s = 3.
3
. 4
.
0 1 1/3 0 2/3 6
0 0 1 1 1 6
1 0 1/3 0 1/3 2
0 0 4/3 0 5/3 16
0 1 0 1/3 1/3 4
0 0 1 1 1 6
1 0 0 1/3 2 /3 4
0 0 0 4/3 1/3 8
NB
2
3
1
NF
5
4
= (4, 4, 6, 0, 0) = , z
min
= 8.
C
2
C
3
C
3
1
0
2
0
C
C
2
k
b
0
k
= 0
0
1
. l = 2 s = 3.
2
. min(, , 6/1). k = 3.
3
. 4
.
0 1 1/3 2/3 0 2
1 0 2/3 1/3 0 0
0 0 1 1 1 6
0 0 1/3 5/3 0 6
0 1 0 1/3 1/3 4
1 0 0 1/3 2/3 4
0 0 1 1 1 6
0 0 0 4/3 1/3 8
NB
2
1
3
NF
4
5
= (4, 4, 6, 0, 0) = , z = 8 = z
min
.
1/4x
1
8x
2
x
3
+ 9x
4
0;
1/2x
2
12x
2
1/2x
3
+ 3x
4
0;
x
3
1;
3/4x
1
+ 20x
2
1/2x
3
+ 6x
4
= z min .