Практикум по методам оптимизации. Компьютерный курс. Семушин И.В. - 67 стр.

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2
. min(, , , 18/4) = 9/2, k = 4.
3
.
5 16/3 0 0 0 5/3 0
3 2 0 1 0 0 0
0 2/3 0 0 1 1/3 0
1 2/3 1 0 0 1/3 0
9/2 1 0 0 0 1/4 1/4
4
. NB(k)
NF (l) :
NB
3
4
2
1
29 0 0 0 0 1/3 4/3
6 0 0 1 0 1/2 1/2
3 0 0 0 1 1/6 1/6
4 0 1 0 0 1/6 1/6
9/2 1 0 0 0 1/4 1/4
NF
6
5
= (9/2, 4, 6, 3, 0, 0) = , 29 = z
min
.
1
NB
3
4
2
1
(7)
29 0 0 0 0 1/3 4/3 0
6 0 0 1 0 1/2 1/2 0
3 0 0 0 1 1/6 1/6 0
4 0 1 0 0 1/6 1/6 0
9/2 1 0 0 0 1/4 1/4 0
6 1 1 0 0 0 0 1
NF
6
5
(3, 4, 2, 1),
1 2
NB
3
4
2
1
7
29 0 0 0 0 1/3 4/3 0
6 0 0 1 0 1/2 1/2 0
3 0 0 0 1 1/6 1/6 0
4 0 1 0 0 1/6 1/6 0
9/2 1 0 0 0 1/4 1/4 0
5/2 0 0 0 0 1/12 5/12 1
NF
6
5
= (9/2, 4, 6, 3, 0, 0, 5/2) 6= , 29 = z.