Химическая термодинамика (задачи, примеры, задания). Захаров И.В - 89 стр.

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89
H
2
O C
2 v
∠HOH=105
o
r
O-H
=0,957
ν
1
=3657
ν
2
=1595
ν
3
=3756
− 241,8
HOCl C
s
∠HOCl=102
o
r
H-O
=0,959
r
O-Cl
=1,689
ν
1
=3609
ν
2
=725
ν
3
=1240
− 92 ± 10
HO
2
C
s
∠HOO=104
o
r
H-O
=0,977
r
O-O
=1,335
ν
1
=3410
ν
2
=1095
ν
3
=1390
23,4 ± 8
O
3
C
2 v
∠OOO=117
o
r
O-O
=1,272
ν
1
=1103
ν
2
=701
ν
3
=1042
142,3 ± 2
H
2
S C
2 v
∠HSH=92
o
r
H-S
=1,336
ν
1
=2615
ν
2
=1183
ν
3
=2625
− 19,2 ± 1
SO
2
C
2 v
∠OSO=118
o
r
S-O
=1,431
ν
1
=1151
ν
2
=518
ν
3
=1362
− 296,8
ClO
2
C
2 v
∠OClO=118
o
r
Cl-O
=1,475
ν
1
=963
ν
2
=452
ν
3
=1133
105 ± 6
Cl
2
O C
2 v
∠ClOCl =
111
o
r
Cl-O
=1,700
ν
1
=640
ν
2
=300
ν
3
=686
78,7 ± 10
KrF
2
D
∞
h
r
Kr-F
=1,889
r
F
…
F
=3,781
ν
1
=449
ν
2
=232,6(2)
ν
3
=588
60,2 ± 4
(40
o
C) 
H2O       C2 v      rO-H=0,957     ν1=3657       − 241,8
       ∠HOH=105o                   ν2=1595
                                   ν3=3756

HOCl      Cs        rH-O=0,959     ν1=3609      − 92 ± 10
       ∠HOCl=102o   rO-Cl=1,689     ν2=725
                                   ν3=1240

HO2       Cs        rH-O=0,977     ν1=3410      23,4 ± 8
       ∠HOO=104o    rO-O=1,335     ν2=1095
                                   ν3=1390

 O3       C2 v      rO-O=1,272     ν1=1103      142,3 ± 2
       ∠OOO=117o                    ν2=701
                                   ν3=1042

H2S      C2 v       rH-S=1,336     ν1=2615      − 19,2 ± 1
       ∠HSH=92o                    ν2=1183
                                   ν3=2625

SO2       C2 v      rS-O=1,431     ν1=1151       − 296,8
       ∠OSO=118o                    ν2=518
                                   ν3=1362

ClO2      C2 v      rCl-O=1,475     ν1=963       105 ± 6
       ∠OClO=118o                   ν2=452
                                   ν3=1133


Cl2O      C2 v      rCl-O=1,700     ν1=640      78,7 ± 10
        ∠ClOCl =                    ν2=300
          111o                      ν3=686

KrF2      D∞ h      rKr-F=1,889     ν1=449      60,2 ± 4
                    rF…F=3,781    ν2=232,6(2)    (40oC)
                                    ν3=588



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