Химическая термодинамика (задачи, примеры, задания). Захаров И.В - 93 стр.

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93
CH
3
I C
3v
∠HCH = 111
o
17′
r
C-H
=1,085
r
C-I
=2,133
ν
1
=2915
ν
2
=1251
ν
3
=533
ν
4
=3062(2)
ν
5
=1438(2)
ν
6
=883(2)
14,6 ± 1
CH
2
O
2
C
s
∠OCO = 125
o
∠H-C=O = 124
o
35′
∠C-O-H = 106
o
50′
r
C-H
=1,097
r
C=O
=1,228
r
C-O
=1,317
r
O-H
=0,974
r
O
…
O
=2,258
Цис транс
ν
1
3570 ν
1
3570
ν
2
2943 ν
2
2943
ν
3
1770 ν
3
1770
ν
4
1387 ν
4
1387
ν
5
1227 ν
5
1229
ν
6
1105 ν
6
1105
ν
7
625 ν
7
638
ν
8
1033 ν
8
1033
ν
9
638 ν
9
582
−379
CHCl
3
C
3v
∠ClCCl = 111
o
18′
∠HCCl = 107
o
34′
r
C-H
=1,100
r
C-Cl
=1,758
ν
1
=3034
ν
2
=680
ν
3
=363
ν
4
=1220(2)
ν
5
=774(2)
ν
6
=261(2)
−103,2 ± 1
CF
4
T
d
r
C-F
=1,322
ν
1
=908;
ν
2
=435(2)
ν
3
=1272(3)
ν
4
=632(3)
−933
CCl
4
T
d
r
C-Cl
=1,766
ν
1
=459
ν
2
=218(2)
ν
3
=776(3)
ν
4
=312(3)
−103
SiH
4
T
d
r
Si-H
=1,480
ν
1
=2185
ν
2
=972(2)
ν
3
=2189(3)
ν
4
=913(3)
35 ± 1 
CH3I          C3v                 ν1=2915         14,6 ± 1
        ∠HCH = 111o17′            ν2=1251
          rC-H=1,085               ν3=533
          rC-I=2,133            ν4=3062(2)
                                ν5=1438(2)
                                 ν6=883(2)


CH2O2           Cs          Цис         транс      −379
         ∠OCO = 125o        ν1 3570    ν1 3570
        ∠H-C=O = 124o35′    ν2 2943    ν2 2943
        ∠C-O-H = 106o50′    ν3 1770    ν3 1770
            rC-H=1,097      ν4 1387    ν4 1387
           rC=O=1,228       ν5 1227    ν5 1229
            rC-O=1,317      ν6 1105    ν6 1105
            rO-H=0,974      ν7 625     ν7 638
           rO…O=2,258       ν8 1033    ν8 1033
                            ν9 638     ν9 582
CHCl3          C3v                ν1=3034        −103,2 ± 1
        ∠ClCCl = 111o18′           ν2=680
        ∠HCCl = 107o34′            ν3=363
           rC-H=1,100           ν4=1220(2)
          rC-Cl=1,758            ν5=774(2)
                                 ν6=261(2)
 CF4            Td                ν1=908;          −933
           rC-F=1,322            ν2=435(2)
                                ν3=1272(3)
                                 ν4=632(3)
CCl4            Td                 ν1=459          −103
           rC-Cl=1,766           ν2=218(2)
                                 ν3=776(3)
                                 ν4=312(3)
SiH4            Td                ν1=2185          35 ± 1
           rSi-H=1,480           ν2=972(2)
                                ν3=2189(3)
                                 ν4=913(3)


                           93

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