Теория вероятностей. Барышева В.К - 47 стр.

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H
p =
1
365
n = 110 λ = np = 110 ·
1
365
= 0.3
P
n
(k) =
λ
k
k!
e
λ
P
110
(k = 0) =
λ
0
0!
e
0.3
= 0.740818;
P
110
(k = 1) =
λ
1
1!
e
0.3
= 0.3 · e
0.3
= 0.222245;
P
110
(k = 2) =
λ
2
2!
e
0.3
=
0.3
2
· e
0,3
2
= 0.033337;
P
110
(k > 1) = 1 P
110
(0) = 1 0.740818 = 0.259182.
N
0.1.
P = 0.964228
p = 0.1 0.01
H
n p = 1.1; q = 0.9; P =
0.96428.
0.01
r
n
0.1 ·0.9
= 0.96428.
Φ
0.01
r
n
0.09
= 0.48214.
Φ(x) 0.48214 = Φ(2.1)
0.01
p
n
0.09
= 2.1 n = 210
2
· 0.09 = 3969. N