Теория вероятностей. Барышева В.К - 48 стр.

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H n p q p
n
P
n
(m) =
1
npq
ϕ(x) ϕ(x) =
1
2π
e
x
2
2
x =
mnp
npq
=
10100·0,2
100·0,8·0,2
=
1020
4
= 2, 5
npq = 4
ϕ(x) ϕ(2, 5) = ϕ(2, 50) = 0, 0175
ϕ(x))
P
100
(10) =
1
4
· 0, 0175 = 0, 004375.
m
1
m
2
x
1
=
m
1
np
npq
=
20 100 · 0.2
4
= 0,
x
2
=
m
2
np
npq
=
100 20
4
= 20.
Φ(x) Φ(x
1
) = Φ(0) = 0, Φ(x
2
) =
Φ(20) = 0.5.
P
100
(20 m 100) = Φ(x
2
) Φ(x
1
) = 0.5.
0 6 m 6 27. x
1
=
020
4
= 5, x
2
=
2720
4
=
7
4
= 1, 75 P
100
(0 6 m 6
27) Φ(1.75) Φ(5) = Φ(1.75) + Φ(5) = 0.45994 + 0.5 = 0.95994