Теория вероятностей. Барышева В.К - 63 стр.

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P (1 < x < 3) = F (3) F (1) = 0.9197 0.3983 = 0.5214.
N
f(x) =
M
2π
exp(
(lg x lg x
0
)
2
2σ
2
),
M = lge = 0.4343 . . .
F (x)
H
F (x) =
x
R
−∞
M
2π
exp(
(lg xlg x
0
)
2
2σ
2
)dx =
=
M
σ
2π
R
x
−∞
exp(
(lg xlg x
0
)
2
2σ
2
)
dx
x
=
=
lg xlg x
0
σ
= t
dt =
1
σ
(lg x)
0
dx =
1
σ
·
1
x
lg e · dx =
M
σ
·
dx
x
;
dx
x
=
M
σ
dt = d
lg xlg x
0
σ
·
M
σ
=
=
M ·σ
σ
2π · M
t
B
Z
−∞
e
1
2
t
2
dt =
1
2π
t
B
Z
−∞
e
t
2
2
dt,
t
B
=
lg x lg x
0
σ
.
N
F (x) =
0, x 6 0
0.35, 0 < x 6 1
0.85, 1 < x 6 2
1, x > 2
x 0 1 2
p 0.35 0.5 0.15