Теория вероятностей. Барышева В.К - 71 стр.

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X
x
p
M[2X + 3], D[3X + 2].
H
M[X] = x
1
p
1
+ x
2
p
2
+ x
3
p
3
+ x
4
p
4
=
= 10 · 0.2 + 20 · 0.15 + 30 · 0.25 + 40 · 0.4 = 28.5.
M[2X + 5] = 2M[X] + M[5] = 2M[X] + 5 = 2 · 28.5 + 5 = 62.
D[X] = M[X
2
] m
2
X
=
= (10
2
· 0.2 + 20
2
· 0.15 + 30
2
· 0.25 + 40
2
· 0.4) (28.5)
2
=
= 945 812.25 = 132.75.
D[3X + 2] = 9D[X] + D[2] = 9D[X] = 9 · 132.75 = 1194.75
σ[X] =
p
D[X] =
132.75 = 11.52.
N