Линейная алгебра. Локтионова Г.Н - 12 стр.

         3 x1 − 5 x2 + 2 x3 + 4 x4 + x5 = 0,    4 x1 − x2 + 5 x3 + x4 = −1,
                                                
     25  7 x1 − 4 x2 + x3 + 3 x4 = 0,            2 x1 − x2 + x3 + 4 x4 = 1,
        5 x + 7 x − 4 x − 6 x − 2 x = 0;         x − x + 3 x + 7 x = 2.
         1         2      3     4      5         1      2     3      4


        6 x1 + 3 x2 + 2 x3 + 3 x4 + 4 x5 = 0,         x1 − x2 + x3 + 3 x4 = −2,
                                                 
     26  4 x1 + 2 x2 + x3 + x4 + 3 x5 = 0,        x1 − 3 x2 − x3 − 3 x4 + 4 x5 = 2,
         2 x + x + x + x + x = 0;                 2 x + 2 x + 3 x − 3 x + 2 x = 1.
              1     2    3     4    5             1        2     3      4      5


         x1 + 2 x2 + 3 x3 − 2 x4 + x5 = 0,       x1 + 7 x2 − 3 x3 + 7 x4 = 3,
                                                
     27  x1 + 2 x2 + 7 x3 − 4 x4 + x5 = 0,      3 x1 + 2 x2 + x3 + 4 x4 = 1,
         x + x + 11x − 6 x + x = 0;              x + 2 x − x + x = 3.
         1      2       3      4    5            1        2     3     4


         x1 + x2 + x3 + 2 x4 + x5 = 0,           2 x1 − x2 + 2 x4 + 3 x5 = 1,
                                                
     28  x1 − 2 x2 − 3 x3 + x4 − x5 = 0,         3 x1 − x2 + x3 + 2 x4 = 5,
         2 x − x − 2 x + 3 x = 0;                x − 5 x − x + x − 3 x = 3;
             1     2      3     4                1      2   3     4      5


         3 x1 + 2 x2 + 4 x3 + x4 + 2 x5 = 0,      x1 − x2 + 3 x3 + x4 = 1,
                                                 
     29  3 x1 + x2 − 2 x3 + x4          = 0,      x1 − 5 x2 − x3 − 4 x4 = 2,
        3 x + 2 x + 16 x + x + 6 x = 0;           2 x − x − x + x = 2.
         1         2       3    4      5          1        2    3     4


         x1 − x2 + x3 − 2 x4 + x5 = 0,           x1 − 2 x2 + 5 x3 + 2 x4 + 3x5 = 1,
                                                
     30  x1 + x2 − 2 x3 − x4 + 2 x5 = 0,         x1 − 3 x2 + x3 + 4 x4 = −5,
         x − 3 x + 4 x − 3 x = 0;                x − 5 x − 3 x + 2 x − 3 x = 2.
         1        2      3     4                 1       2      3      4     5




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