Компьютерная обработка информации (в пакете MathCAD). Мартьянова А.Е. - 27 стр.

Мартьянова А.Е. Компьютерная обработка информации                                                 27




2.3.3. Матричное решение задачи

          Дано:
 P := 2      Q := 1         L := 3        h := 1

 N := Q      XA := P        YA := P

         Решение:



  XA − N ⋅ cos ( 60 ⋅ deg)       0

  YA − P + N ⋅ cos ( 30 ⋅ deg) − Q          0

         L                          N⋅h
  −P ⋅     ⋅ cos ( 30 ⋅ deg) +                 − Q ⋅ L ⋅ cos ( 30 ⋅ deg)   0
         2                     sin ( 30 ⋅ deg)




     ⎛ 1 0 −cos ( 60 ⋅ deg)          ⎞        ⎛                       0                           ⎞
     ⎜                                        ⎜
       0 1 cos ( 30 ⋅ deg)                                         Q+P
A := ⎜                               ⎟   D := ⎜                                                   ⎟
     ⎜             h                 ⎟        ⎜    L                                              ⎟
     ⎜ 0 0                                    ⎜ P ⋅ ⋅ cos ( 30 ⋅ deg) + Q ⋅ L ⋅ cos ( 30 ⋅ deg)
     ⎝      sin ( 30 ⋅ deg)          ⎠        ⎝    2                                              ⎠

           −1
  X := A        ⋅D

      ⎛⎜ 1.299 ⎞
  X = ⎜ 0.75 ⎟
       ⎜ 2.598                               X := lsolve ( A , D)
       ⎝       ⎠
                                                 ⎛⎜ 1.299 ⎞
                                             X = ⎜ 0.75 ⎟
                                                  ⎜ 2.598
                                                  ⎝       ⎠