Квантовая механика. Мокшин А.В - 20 стр.

UptoLike

υ υ +
dN = f (u)du,
λ = 2π¯h/mυ
F (λ) f(u)
λ λ +
υ υ +
dN = F (λ)dλ.
F (λ) = f(u)du.
F (λ) = f(u)
du
.
u = 2π¯h/mλυ
F (λ) = A
2π¯h
3
λ
3
e
2π¯h
2
λ
2
·
2π¯h
λ
2
=
= Bλ
5
exp
2π
2
¯h
2
mkT λ
2
.
B
F (λ)
dF/dλ = 0.
5λ
6
+
4π
2
¯h
2
mkT
λ
8
= 0.
              !      8 -   % !     !  ,     23  9 '-  (
  +         / %           1 %  8         ! $!    - * @B 23 9    
                           υ υ + dυ

                                              dN = f (u)du,
                                                                                                             /D 1




    2;     ( N  "     ,   & ' 2 λ = 2πh̄/mυ 5
          K  8       3 "   ! 8        3    8 -  8    .   "   (
  !  )    6                  %:  $ 0 ! 8        '8 $!     !          5
                                 F (λ)                                                          f (u)
   !     & ''8 -   %   .   "   !      2C   ,     23  9' '
-    B     ,/ λ % λ + dλ1!      !  - * @ 6     -0!     !   "
    / υ % υ + dυ 1 %  
                                                                                                 /DG 1
                                             dN = F (λ)dλ.
 ?    '      23 23 9  0/ D 1+/ D G 1 % 8   -     




                                           F (λ)dλ = f (u)du.
        P3 ! *3
                                                                       du                                 /D 1
                                             F (λ) = f (u)                .
        : 7                            5?  !             
                                                                         '    
                                                                       dλ
                                                                                       $/ D  1 % 8   -  (
                   u = 2πh̄/mλυ
 
                                                                                2
                                                                    2πh̄
                                                              
                           
                                2πh̄
                                        3                −
                                                                   mϑ
                                                                                   λ−2
                                                                                                2πh̄
                                                                                                 
                                                 −3
                                                                                                            
    F (λ)          =   A                     λ        e                                    ·            −λ−2 =
                               mϑ                                                              mϑ
                                  2π 2 h̄2                                                                   /DH1
                                          
                   =   Bλ−5 exp −            .
                                  mkT λ2
7  '   ## 4    B   *  2; !   !   25
          .           ,   '   C
                                                   2   ( N   "  $8 -  '   &  (
      !  - !    ,  ! - '#-  4             
                                                                                F (λ)

                                                 dF/dλ = 0.
P  ! *3 %  ##   4   - 0/ D H 18   - 3%

                                                          4π 2 h̄2 −8
                                        −5λ−6 +                   λ = 0.
                                                          mkT
                                                              F