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V
3
(a, b) = g
11
a
1
b
1
+ g
12
a
1
b
2
+ g
13
a
1
b
3
+ g
21
a
2
b
1
+ g
22
a
2
b
2
+
+ g
23
a
2
b
3
+ g
31
a
3
b
1
+ g
32
a
3
b
2
+ g
33
a
3
b
3
.
V
2
(a, b) = g
11
a
1
b
1
+ g
12
a
1
b
2
+ g
21
a
2
b
1
+ g
22
a
2
b
2
.
{e
i
} |e
i
| =
1 i, j = 1, 2, 3, e
i
⊥ e
j
i 6= j
(g
ij
) g
ij
=
δ
ij
V
3
V
2
(a, b) = a
1
b
1
+ a
2
b
2
+ a
3
b
3
,
(a, b) = a
1
b
1
+ a
2
b
2
.
ABC AA
1
BB
1
CB CA
• •
•
• •
•
A B
B
1
A
1
C
O
|
−−→
AA
1
| = |
−−→
BB
1
| = 3
O
{O, e
i
}
e
1
=
−−→
OA
1
e
2
=
−−→
OB
1
−−→
CB = 2
−−→
A
1
B = 2(
−−→
A
1
O +
−−→
OB) = 2{−1; −2} =
{−2; −4}
−→
CA = 2
−−→
B
1
A = 2(
−−→
B
1
O+
−→
OA) = 2{−2; −1} =
{−4; −2}
cos ∠C =
16
(
√
20)(
√
20)
=
4
5
/-/86b7*,,2J 0[ /16793,N .3-0[b*L*,0M ã b*18-3-b +6[0/6= 79 .3-K /836,/8b6 V b 36[b*3,28-; b0L* O-3;276 _ b:79L08 /7*L2J}0; -+K 36[-; 3 (a, b) = g11 a1 b1 + g12 a1 b2 + g13 a1 b3 + g21 a2 b1 + g22 a2 b2 + a + g23 a2 b3 + g31 a3 b1 + g32 a3 b2 + g33 a3 b3 . { /72)6* .7-/1-/80 V \ /--8b*8/8b*,,-\ 0;**; 2 (a, b) = g11 a1 b1 + g12 a1 b2 + g21 a2 b1 + g22 a2 b2 . ` ϳTxwxxXWxZ ü¢ {e } ¢£ ¥ |e | = 1 ¥ i, j = 1, 2, 3, e ⊥ e ¡ i 6= j = i i { /72)6* -38-,-3;03-b6,,-:- +6[0/6 ;6830 6 (g ) · *L0,0),69\ g = i j δ \ 0 /16793,* .3-0[b*L*,09 b*18-3-b b V 0 V ,6N-L98/9\ /--8b*8/8b*,K ij ij ,-\ .- /7*L2J}0; O-3;276; ij 3 2 (a, b) = a1 b1 + a2 b2 + a3 b3 , (a, b) = a1 b1 + a2 b2 . Z TWµxTUZ H30b*L*; .30;*3\ 077J/83032J}0* .30;*,*,0* O-3;27 _= ðÍwÍñÍ r±Z { 36b,-+*L3*,,-; 83*2:-7?,01* ABC ;*L06, AA 0 BB \ .3-b*L*,,* 1 +-1-b; 36b,; /8-3-,6; CB 0 CA \ .*3*/*16J8/9 .-L 1 1 .39;; 2:7-;= 6M80 2:7 ~8-:- 83*2:-7?,016= àxÿxXWxZ ;= 30/2,-1 ]Ú = H-/1-7?12 b/* 83*K 2:-7?,010\2L-b7*8b-39J}0* 2/7-b09; [6L6)0\.-K C • L-+,\ +2L*; /)0868?\ )8- |−AA −→ | = |BB | = 3 = −−→ H2/8? O · 8-)16 .*3*/*)*,09 ;*L06,= {b*L*; ,6 1 B A 1 1 1 .7-/1-/80 -38-,-3;03-b6,,M 3*.*3 {O, e } \ bK • • • +36b [6 b*18-3 +6[0/6 e = −OA−→ \ e = OB = -K −−→ O i :L6 −CB −→ −−→ −−→ −−→ 1 = 2A B = 2(A O + OB) = 2{−1; −2} = 1 2 1 • • \ −→ 1 −−→ −−→ −→ 1 {−2; −4} CA = 2B A = 2(B O+OA) = 2{−2; −1} = A 0/ ]Ú Ç = = B {−4; −2} = 8/JL6 ,6N-L0; 1 cos ∠C = 1 = = √ 16√ 4 5 ( 20)( 20) ¾
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