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3. Варианты заданий контрольной работы 3
№
варианта
1 задача 2 задача 3 задача
1
=
=
4/18/1
5/15/2
;
5,0
1
A
C
=
=
=
=
28
14
;
1510
55
)1,1(;
104
25
SB
PA
2/1,10 =α=A
2
=
=
4/13/1
4/13/1
;
5,0
1
A
C
=
=
=
=
28
14
;
155
55
)5,1(;
104
25
SB
PA
2/1,10
3
=α=A
3
=
=
4/12/1
6/13/1
;
3
1
A
C
=
=
=
=
18
22
;
210
610
)2,1(;
1212
57
SB
PA
3/1,10
3
=α=A
4
=
=
4/14/1
4/12/1
;
1
3
A
C
=
=
=
=
30
30
;
43
22
)6,2(;
12
21
SB
PA
3/1,10
2
=α=A
5
=
=
3/13/1
5/15/2
;
5
1
A
C
=
=
=
=
12
9
;
44
32
)3,2(;
13
21
SB
PA
3/1,10 =α=A
6
=
=
5/25/1
8/14/1
;
2
1
A
C
=
=
=
=
12
9
;
44
23
)3,2(;
31
12
SB
PA
4/1,10 =α=A
7
=
=
3/14/1
3/14/1
;
2
4
A
C
=
=
=
=
20
20
;
1015
55
)1,1(;
410
52
SB
PA
4/1,10
2
=α=A
8
=
=
3/16/1
2/14/1
;
2
6
A
C
=
=
=
=
28
14
;
515
55
)5,1(;
410
52
SB
PA
2/1,10
2
=α=A
