Линейные операторы в квантовой механике. Кирсанов А.А. - 45 стр.

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45
1
4
3
8
6
32
4sin
4
2sin
8
3
sin
22
2
0
2
2
0
42
=
π
=
π
=
ϕ
+
ϕ
ϕ
=ϕϕ
π
π
AAAdA
,
откуда
π
=
3
4
2
A
.
( )
=ϕϕ
ϕ
ϕ=ϕϕϕ=
ππ 2
0
2
2
2
222
2
0
2222
sinsinsin
sin
dAdALAL
zz
h
( )
=ϕϕϕϕ=
=ϕ=ϕ=ϕ
ϕ
=ϕ
ϕ
=
ππ 2
0
422
2
0
222
22
2
2
sin4sin2
sin2122cos22sinsin
dAdA hh
=
ϕ
+
ϕ
ϕ
=
ϕ
ϕ
=
ππ 2
0
22
2
0
22
32
4sin
4
2sin
8
3
4
4
2sin
2
2 hh AA
2
22
222222
3
2
24
3
2
8
23
4
2
2
2 h
h
hhh =
π
=
ππ=
π
π
=
A
AAA
.
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                                                                                    45
    2π                                                      2π
                                  2  3ϕ
                           sin 2ϕ sin 4ϕ    2 6π 3π 2
     ∫ A sin ϕdϕ = A  8 − 4 + 32  = A 8 = 4 A = 1,
          2        4

     0                                     0

                            4
    откуда A =
            2
                              .
                           3π
                  2π                                   2π
     L€2z =              2   2
                                   (2
                                            )
                  ∫ A sin ϕL€z A sin ϕ dϕ = − A h ∫ sin ϕ
                                               2 2     2          ∂2
                                                                 ∂ϕ 2
                                                                      sin 2 ϕdϕ =
                  0                                    0



    =
          ∂2
         ∂ϕ 2
              sin 2 ϕ =
                         ∂
                        ∂ϕ
                                                       (
                           sin 2ϕ = −2 cos 2ϕ = −2 1 − 2 sin 2 ϕ =  )
                      2π                    2π
    = 2 A 2 h 2 ∫ sin 2 ϕdϕ − 4 A2 h 2 ∫ sin 4 ϕdϕ =
                       0                    0


                                       2π                                 2π
            ϕ sin 2ϕ 
                  2         2 2  3ϕ sin 2ϕ sin 4ϕ 
    = 2A h  −2
                      = −4 A h  −         +        =
           2    4 0             8     4     32  0

                       2π            3 ⋅ 2π                3  A2 h 2 π 2 2
    = 2 A2 h 2            − 4 A2 h 2        = 2 A2 h 2  π − π  =      = h .
                        2               8                  4     2     3




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