Тепловой расчет и тепловой баланс карбюраторного двигателя и двигателя с впрыском топлива. Мелисаров В.М - 66 стр.

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
= P
zd
/F
x-x
= 0,0296 / 0,00096 = 30,8 ,

P
zd
= p
zd
F
= 5,7628 ⋅ 47,76 ⋅ 10 – 6 = 0,0269 MH;
F
x-x
= (/4) (d
2
k
– d
2
i
) – n′
m
F ′ = 0,00096
2
;
d
x
= D – 2(t +t) = 82 – 2 ⋅ (3,5 +0,8) = 73,4 ;
F’ = (d
x
– d
i
) d
m
/ 2 = 4,6 
2
.
   х–х :
    
. . max
= n
. . max
/ 30 = 3,14 ⋅ 6000 / 30 = 628 /.
   ,    х–х:
M
x-x
= 0,5m
= 0,5 ⋅ 0,4776 = 0,2388 .
  
P = m
x-x
R
2
x.
x.
max
(1 + ) = 0,2388 ⋅ 0,039 ⋅ 628
2
⋅ (1 + 0,285) ⋅ 10
–6
= 0,00472 .
 
= Р
j
/ F
x-x
= 0,00472 / 0,00096 = 4,917 .
   :
– 
= 0,0314P
zd
D / hc = 0,0314 ⋅ 5,7628 ⋅ 82/3,5 = 4,24 ;
– 

= 0,0045p
zd
(D / hп)
2
= 0,0045 ⋅ 5,7628 ⋅ (82/3,5)
2
= 14,234 ;
– 
= +σ
2

4
2
= 16,57 .
     :
q
1
= 0,0044 / (0,58 ⋅ 0,082) = 0,925 ;
q
2
= 0,0044 / (0,088 ⋅ 0,082) = 0,610 .
   ,       –  
–   –       ,   -
 .
         -
           
  
.
      :
D
= D –
= 82 – 0,574 = 81,43 ;
= 0,007D = 0,007 ⋅ 82 = 0,574 ;
D
= D –
= 82 – 0,164 = 81,84 ;
= 0,002D = 0,164 .
   :
′
= D [1 +
(Т
– Т
)] – D
[1 +
(Т
r
– Т
)] = 82,08 – 81,97 = 0,1126 ;
′
= D [1 +
(Т
– Т
)] – D
[1 +
(Т
– Т
)] = 82,08 – 82,056 = 0,0239 ,
 Т
= 383 , Т
r
= 593 , Т
= 413     .
3.1.1.     
  –   , Е = 1,2 ⋅ 10
5
.
     

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