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Составители:
Рубрика:
63
ЗАДАЧИ
Выполнить задания, сформулированные в примере, для следующих типов
сигналов:
1.
()
ststtt()exp/,..=−
=000001
2
2. st
s
tt
t()
cosh(/)
,..=
+
=
0
10
00004
3.
[]
st
s
tt
t()
exp(/)
,..=
+
=
0
10
00013
2
2
4.
(
)
[]
st
st
tt
t()
exp(/)
,.,..=
+
+
==
01
10
08300012
2
2
2
β
β
5.
(
)
[]
st
st
tt
t()
cosh(/)
,.,..=
+
+
==
01
10
00008117
2
2
β
β
6.
(
)
[]
st
st
tt
t()
||
cos(/)
,.,..=
+
+
==
01
10
07400007
2
β
β
7.
st
s
tt
t()
|sinh(/)|
,..=
+
=
0
10
00011
2
8.
(
)
st
st
tt
t()
|sinh(/)|
,.,..=
+
+
==
01
10
0570001
2
2
β
β
9.
st
s
tt
t()
|sinh(/)|
,..=
+
=
0
10
000077
2
10.
(
)
st
st
tt
t()
||
|sinh(/)|
,.,..=
+
+
==
01
10
000081287
2
β
β
11. st
s
aa
ta
tttt
()
||
,.,..
//
=
+−
==
−
20
2
000123237
002
12.
()
st
s
aa
ta
tttt
(),.,..
//
=
++
==
−
20
2
000053303
00
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63
ЗАД АЧ И
В ы п ол ни ть зад ани я, сформ у л и рованны е вп ри м ере, д л ясл ед у ющ и х ти п ов
си гнал ов:
1. s(t ) = s0 exp −(t / t 0)
2
, t 0 = 0.01.
s0
2. s(t ) = , t 0 = 0.004.
1 + cosh(t / t 0 )
s0
3. s(t ) = , t 0 = 0.013.
[ 1 + exp(t / t 0 )2
2
]
4. s(t ) =
(
s 0 1 + βt 2 ) , β = 0.83, t 0 = 0.012.
[1 + exp(t / t 0 )2
2
]
5. s(t ) =
(
s0 1 + βt 2 ) , t 0 = 0.008, β = 117
. .
[1 + cosh(t / t 0 )] 2
s0(1 + β| t |)
6. s(t ) = , β = 0.74, t 0 = 0.007.
[1 + cos(t / t 0 )]2
s0
7. s (t ) = , t 0 = 0.011.
1+|sinh(t / t 0 )| 2
8. s(t ) =
(
s0 1 + βt 2 )
, β = 0.57, t 0 = 0.01.
1+|sinh(t / t 0 )|2
s0
9. s(t ) = , t 0 = 0.0077.
1+|sinh(t / t 0 )|2
s 0(1 + β| t |)
10. s(t ) = , t 0 = 0.0081, β = 2.87.
1+|sinh(t / t 0 )|2
2 s0
11. s(t ) = , t 0 = 0.0123, a = 2.37.
2 +| at / t 0 − a−t / t 0 | 2
2s0
12. s(t ) = , t 0 = 0.0053, a = 3.03.
(
2 + at / t 0 + a−t / t 0 )
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