Практикум по теории управления в среде MATLAB. Никульчев Е.В. - 48 стр.

11      ⎧ 1 ⎛ 5 3 ⎞ 1 ⎛ − 1⎞ 1                                                                                                         5
        ⎪ x = ⎜⎜    ⎟⎟ x + ⎜⎜ ⎟⎟u                                     ⎧ 3 ⎛1                  2⎞ 3 ⎛1⎞ 3
        ⎪       ⎝ 2 1⎠       ⎝3 ⎠     ⎧⎪− x3 + 3 x 3 − 2 x3 = 2u    ⎪ x = ⎜⎜                  ⎟ x + ⎜⎜ ⎟⎟u
     1. ⎨                          2. ⎨ 3                           3. ⎨       ⎝3              2 ⎟⎠      ⎝ 2⎠
        ⎪ y1 = ⎛⎜ 1 2 ⎞⎟ x1            ⎪⎩ y = x  3
                                                                       ⎪ 3
                                                                       ⎩ y = (− 1               2)x   2
        ⎪       ⎜ 2 − 1⎟
        ⎩       ⎝       ⎠
12                                      ⎧ 2 ⎛1 2⎞ 2 ⎛ 1 5⎞ 2             ⎧ 3 ⎛ 1 2 ⎞ 3 ⎛14 ⎞ 3                                         7
        ⎧⎪− x3 + 2 x 3 − x 3 = 4u    ⎪ x = ⎜⎜   ⎟⎟ x + ⎜⎜       ⎟⎟u  ⎪ x = ⎜⎜   ⎟⎟ x + ⎜⎜ ⎟⎟u
     1. ⎨ 3                          2. ⎨       ⎝3 2⎠       ⎝ − 2 1 ⎠ 3. ⎨       ⎝3 2⎠       ⎝1⎠
         ⎪⎩ y = x  3
                                        ⎪ 2                              ⎪ 3
                                        ⎩ y = (4 3)x                     ⎩ y = (5 2 )x
                                                       2                                2


13                                    ⎧ 2 ⎛ − 1 2 ⎞ 2 ⎛ 1 − 1⎞ 2      ⎧ 3 ⎛1 2 ⎞ 3 ⎛ − 4⎞ 3                                            6
        ⎧⎪x3 + 2 x 3 − x3 = −2u    ⎪ x = ⎜⎜    ⎟⎟ x + ⎜⎜     ⎟⎟u  ⎪ x = ⎜⎜        ⎟⎟ x + ⎜⎜ ⎟⎟u
     1. ⎨ 3                        2. ⎨       ⎝ 3 2⎠       ⎝ 2 1 ⎠ 3. ⎪       ⎝3 − 2⎠          ⎝ 1 ⎠
         ⎪⎩ y = x 3                                                   ⎨
                                      ⎪ 2                             ⎪ y 3 = ⎛⎜ 5 − 1⎞⎟ x 2
                                      ⎩ y = (− 2 3)x
                                                       2
                                                                      ⎪        ⎜       ⎟
                                                                                       ⎩       ⎝3 1 ⎠
14      ⎧⎪ x11 = 2 x12 + u             ⎧⎪ y11 = x11          ⎧ 2 ⎛1 2 ⎞ 2 ⎛ 1 5⎞ 2                ⎧ 3 ⎛1 2 ⎞ 3 ⎛ − 4⎞ 3               8
                                                                                                   ⎪ x = ⎜⎜        ⎟⎟ x + ⎜⎜ 1 ⎟⎟u
     1. ⎨ 1                              ⎨ 2               2. ⎪ x = ⎜⎜ 3 2 ⎟⎟ x + ⎜⎜ 2 1 ⎟⎟u 3.   ⎪       ⎝3 − 2⎠          ⎝ ⎠
         ⎪⎩ x2 = − x11 + 3 x12 − u      ⎪⎩ y1 = x1 − 2 x2
                                                    2    1    ⎨       ⎝      ⎠      ⎝      ⎠       ⎨
                                                              ⎪                                    ⎪ y 3 = ⎛⎜ 5 − 1⎞⎟ x 2
                                                                ⎩ y = (4 3)x
                                                                   2         2
                                                                                                   ⎪        ⎜3 1 ⎟
                                                                                                   ⎩        ⎝       ⎠
15                                                            ⎧ 2 ⎛1 2⎞ 2 ⎛ 1 −1⎞ 2                                                    8
                                                                                                   ⎧ 3 ⎛1 2 ⎞ 3 ⎛ − 4⎞ 3
        ⎧⎪x11 = −2x12 + 2u            ⎧⎪ y11 = − x11         ⎪x = ⎜⎜     ⎟x + ⎜⎜      ⎟u
                                                                       3 2⎟⎠       2 1 ⎟⎠ 3.       ⎪ x = ⎜⎜         ⎟⎟ x + ⎜⎜   ⎟⎟u
     1. ⎨ 1                             ⎨ 2                2. ⎨      ⎝           ⎝                 ⎪       ⎝3 − 2⎠           ⎝ 1 ⎠
         ⎪⎩x2 = − x11 + 3x12 − u       ⎪⎩ y1 = x12 − 2x12    ⎪ 2                                  ⎨
                                                              ⎩y = (− 4 3)x                        ⎪ y 3 = ⎛⎜ 5 − 1 ⎞⎟ x 2
                                                                              2
                                                                                                   ⎪        ⎜3 1 ⎟
                                                                                                   ⎩        ⎝        ⎠
16      ⎧ 1 ⎛ 5 3 ⎞ 1 ⎛ − 1⎞ 1                                                               ⎧ 3 ⎛1 2⎞ 3 ⎛ 1 ⎞ 3                       9
        ⎪ x = ⎜⎜     ⎟⎟ x + ⎜⎜ ⎟⎟u    ⎧⎪ x12 = 3 x12 − 2 x22 + 3u      ⎧⎪ y11 = − x11      ⎪ x = ⎜⎜   ⎟⎟ x + ⎜⎜ ⎟⎟u
     1. ⎪       ⎝ 2 1⎠        ⎝ 3 ⎠ 2. ⎨                                  ⎨ 2             3.
        ⎨                                                                                    ⎨       ⎝3 2⎠       ⎝ 2⎠
                                        ⎪⎩ x22 = − x12 + 3 x22 − u       ⎪⎩ y1 = x1 − x2
                                                                                    2   1
                                                                                             ⎪ 3
        ⎪ y 1 = ⎛⎜ 1 2 ⎞⎟ x1
                                                                                               ⎩ y = (− 1 2 )x
                                                                                                              2
        ⎪        ⎜ 2 − 1⎟
        ⎩        ⎝       ⎠
17      ⎧⎪ x11 = x11 + 4 x12 + 3u        ⎧⎪ y11 = − x11 + 2 x12    ⎧ 2 ⎛1 2⎞ 2 ⎛ 1 5⎞ 2                                               10
     1. ⎨ 1                                                      2. ⎪ x = ⎜⎜   ⎟⎟ x + ⎜⎜       ⎟⎟u
                                           ⎨ 2                      ⎨       ⎝3 2⎠       ⎝ − 2 1 ⎠ 3.
         ⎪⎩ x2 = − x11 + 3 x12 − 2u       ⎪⎩ y1 = x1 − x2
                                                     2     1
                                                                    ⎪ 2
                                                                  ⎩ y = (4 3)x
                                                                                   2



     ⎧ 3 ⎛ 1 2 ⎞ 3 ⎛ 14 ⎞ 3
     ⎪ x = ⎜⎜   ⎟⎟ x + ⎜⎜ ⎟⎟u
     ⎨       ⎝3 2⎠       ⎝1⎠
     ⎪ 3
     ⎩ y = (5 2 )x
                     2



18                                                                  ⎧ 2 ⎛ − 1 2 ⎞ 2 ⎛ 1 − 1⎞ 2                                         8
        ⎧⎪ x11 = x11 − 4 x12 + 3u        ⎧⎪ y11 = − x11 + 5 x12    ⎪ x = ⎜⎜      ⎟ x + ⎜⎜      ⎟u
     1. ⎨ 1                                ⎨ 2                   2. ⎨       ⎝ 3 2 ⎟⎠      ⎝ 2 1 ⎟⎠
         ⎪⎩ x2 = − x11 + 3 x12 − 4u       ⎪⎩ y1 = x12 − x12        ⎪ 2
                                                                    ⎩ y = (− 2 3)x
                                                                                      2


          ⎧ 3 ⎛1          2 ⎞ 3 ⎛− 4⎞ 3
          ⎪ x = ⎜⎜           ⎟ x + ⎜⎜   ⎟⎟ u
     3.   ⎪       ⎝3     − 2 ⎟⎠      ⎝ 1 ⎠
          ⎨
          ⎪ y 3 = ⎛⎜ 5   − 1⎞ 2
                   ⎜3       ⎟x
          ⎪
          ⎩        ⎝     1 ⎟⎠




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