Линейная алгебра и комплексные числа. Варианты заданий к практическим занятиям. Сирота Ю.Н. - 104 стр.

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,,,[], = y − z 2 = x − 3 z 8[ ], = x + zt = y − − 2 z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
8-7
-6 -7
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-4 -4
4-3
VARIANT 14 = z
1
+ -20 8 I = z
2
− −
2
2
1
2
I
2 = K -11 [ ],,-4 5 -4 [ ],,-1 0 -1,, , , , , ,
[],,54-5
,,,[], = y − z 1 = x − z 4[ ], = y − − zt = x + 3 z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-9 -1
37
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-3 -2
-1 1
,, , , , , ,VARIAN
T
15 = z
1
+ 45 15
I
= z
2
1
=
K
72 [ ],,324 [ ],,-4 0 2 [ ],,-1 -2 -5
,,,[], = x + 12z = y − − 53z [], = y − − 3 z 3 t = x − + 2 z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
8-5
7-7
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
32
-1 -4
VARIANT 16 = z
1
− 27 22 I = z
2
+
2
2
1
2
I
2 = K -921 [ ],,0-3-2 [ ],,-4 -3 1,, , , , , ,
[],,-1 -5 -2
,,,[], = x − 32z = y + 1 z [], = y − 3 z 2 t = x + z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
5-9
-4 -4
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-4 -1
1-2
,, , , , , ,VARIANT 17 = z
1
− -6 29 I = z
2
− +
1
2
1
2
I
3 = K -1 [ ],,3-33 [ ],,-5 5 -4 [ ],,4-3-2
,,,[], = x + 2 z 7 = y + 2 z 6[ ], = y − z 2 t = x − + 3 z 2 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
18
24
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-3 2
42
,, , , , , ,VARIANT 18 = z
1
− -42 70 I = z
2
+
2
2
1
2
I
2 = K 27 [ ],,-4 1 1 [ ],,132 [ ],,-2 2 0
,,,[], = y − + 6 z = x − + z 4[ ], = x + zt = y + 2 t 3 z = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
91
9-9
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-3 3
41
,, , , , , ,VARIANT 19 = z
1
+ 8 I = z
2
− +
1
2
1
2
I
3 = K 240 [ ],,-4 -3 5 [ ],,5-25 [ ],,2-30
,,,[], = y − + 62z = x − z 1[ ], = x − + 2 zt = y + zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-4 -1
-8 8
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
44
-3 2
,, , , , , ,VARIAN
T
20 = z
1
− -21 59
I
= z
2
I
=
K
-82 [ ],,3-15 [ ],,2-1-1 [ ],,2-32
,,,[], = y − 3 z 1 = xz[], = x − − 2 z 3 t = y − + 3 zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-8
3-2
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-4 3
-1 4
,, , , , , ,VARIANT 21 = z
1
+ 42 7
I
= z
2
1
=
K
-1 [ ],,-5 -1 5 [ ],,0-35 [ ],,-2 0 -1
,,,[], = x − + z 1 = y − + 2 z 8[ ], = y − z 2 t = x + zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-3 6
47
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-3
-2 3
VARIANT 22 = z
1
− -62 50 I = z
2
− −
2
2
1
2
I
2 = K -11 [ ],,-2 -3 -3 [ ],,0-42,, , , , , ,
[],,2-5-3
,,,[], = x + 2 z 6 = y − + z 1[ ], = y − zt = x − + 3 t 3 z = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
1-1
-6 9
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
21
-3 -4
VARIANT 23 = z
1
− -102 103 I = z
2
− +
1
2
1
2
I
3 = K 240 [ ],,-1 -1 -3 [ ],,204,, , , , , ,
[],,4-32
,,,[], = y + 93z = x + 22z [], = y − − 2 zt = x − − z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
78
-2 -8
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
2-3
23
,, , , , , ,VARIANT 24 = z
1
− -51 75
I
= z
2
-1
=
K
300 [ ],,4-4-3 [ ],,-1 -4 2 [ ],,0-22
,,,[], = y − − 3 z 1 = x − + z 1[ ], = y − + 3 t 3 z = x − − 3 z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
12
-4 1
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
4-2
-2 2
VARIANT 25 = z
1
+ -30 61 I = z
2
− +
1
2
1
2
I
3 = K -1 [ ],,2-1-4 [ ],,-3 -5 -1,, , , , , ,
[],,-1 2 -3

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