Линейная алгебра и комплексные числа. Варианты заданий к практическим занятиям. Сирота Ю.Н. - 103 стр.

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,, , , , , ,VARIAN
T
1 = z
1
− 12 4
I
= z
2
1
=
K
44 [ ],,-3 -2 -1 [ ],,32-3 [ ],,-5 3 -5
,,,[], = x −z = y + z 2[ ], = x + 3 zt = y − − 2 z 2 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
56
33
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
2-1
-4 3
,, , ,,,,VARIANT 2 = z
1
+ -78 38 I = z
2
+
2
2
1
2
I
2 = K -3 [ ],,125 [ ],,210 [ ],,0-3-3
,,,[], = y − 72z = x − + 62z [], = y − + zt = x − − 3 z 2 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-6 3
-6 6
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-1 -3
21
,, , ,,, ,VARIANT 3 = z
1
− 70 59 I = z
2
− +
1
2
1
2
I
3 = K 240 [ ],,21-2 [ ],,-5 4 -2 [ ],,131
,,,[], = y − + 2 z 1 = x − + z 1[ ], = x − + z 3 t = y − 3 zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-3
65
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-1 -4
4-3
VARIANT 4 = z
1
+ -10 34 I = z
2
− +
2
2
1
2
I
2 = K 713 [ ],,1-32 [ ],,-1 -2 -2,, , , , , ,
[],,140
,,,[], = xz = y − − z 2[ ], = y + 2 zt = x + 2 zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-8 -9
-8 8
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
4-4
12
,, , , , , ,VARIAN
T
5 = z
1
+ 25 97
I
= z
2
1
=
K
11 [ ],,14-2 [ ],,113 [ ],,-1 -5 5
,,,[], = y −z = x − 3 z 4[ ], = x − + z 2 t = y + 3 zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
19
-6 -8
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-4 2
-1 -1
,, , , , , ,VARIANT 6 = z
1
+ 25 61
I
= z
2
I
=
K
-16 [ ],,234 [ ],,40-2 [ ],,10-3
,,,[], = x − − 1 z = y + 93z [], = x − z 2 t = y − − 3 zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-9 -7
3-5
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-3
-3 -3
,, , , ,,,VARIANT 7 = z
1
+ -41 22 I = z
2
− −
1
2
1
2
I
3 = K 240 [ ],,413 [ ],,432 [ ],,-3 -5 -1
,,,[], = x − 72z = y − 6 z
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
, = xx = y + −
3
x
2
z
2
7 t
2
= X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-5 2
49
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-2
1-4
,, , , , , ,VARIANT 8 = z
1
− 13 4 I = z
2
−
2
2
1
2
I
2 = K -324 [ ],,334 [ ],,4-34 [ ],,-3 -1 2
,,,[], = x + 52z = y − − z 2[ ], = x − 2 z 3 t = y − + zt = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
29
-9 -1
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-1 -2
-1 2
,, , , , , ,VARIANT 9 = z
1
+ -51 166 I = z
2
− −
1
2
1
2
I
3 = K 5[ ],,220 [ ],,-5 -1 3 [ ],,-5 1 -2
,,,[], = y − + z 4 = x − 3 z 11 [ ], = y − + 3 t 3 z = x + 2 t 3 z = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-4
-2 6
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-4 2
3-2
VARIANT 10 = z
1
− 28 2 I = z
2
− −
2
2
1
2
I
2 = K -16 [ ],,0-31 [ ],,-4 -5 -3,, , , , , ,
[],,-2 5 2
,,,[], = x − 52z = y − 3 z 4[ ], = x − + 2 zt = y + z 2 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-8 9
69
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-3 -3
-2 -4
VARIANT 11 = z
1
+ -62 83 I = z
2
+
1
2
1
2
I
3 = K 240 [ ],,-5 -3 -5 [ ],,30-3,, , , , , ,
[],,-2 -2 -1
,,,[], = x − 3 z 11 = y − 52z [], = y + 2 z 2 t = x − + 2 z 3 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-6 -7
-1 -3
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-2 -4
-4 2
,, , , , , ,VARIAN
T
12 = z
1
− 33 89
I
= z
2
-1
=
K
-121 [ ],,-2 -1 -1 [ ],,-1 1 1 [ ],,-1 2 -1
,,,[], = y + z 2 = xz[], = x − + 2 zt = y − 3 z 2 t = X
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
3-6
-8 -8
= Y
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
-2 3
-3 2
,, , ,,,,VARIANT 13 = z
1
− -1 153 I = z
2
− +
1
2
1
2
I
3 = K 11 [ ],,5-52 [ ],,-3 4 2 [ ],,-4 1 -5

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