Аналитическая геометрия и линейная алгебра. Умнов А.Е. - 347 стр.

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                                                    α •11•1 = α •111γ 11 + α •121γ 21 =3 ⋅ 5− 4 ⋅ 3 = 3
                                                    α •12•1 = α •111γ 12 + α •121γ 22 = −3 ⋅ 3 + 4 ⋅ 2 = −1
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                                                               2 11
                                                                    + α •221γ 21 =5 ⋅ 5 − 7 ⋅ 3 = 4
                                                    α •22
                                                        •1 = α •11γ
                                                               2 12
                                                                    + α •221γ 22 = 5 ⋅ (−3) + 7 ⋅ 2 = −1
                                                                                                                       
                                                    α •11•2 = α •112γ 11 + α •122γ 21 =2 ⋅ 5 − 3 ⋅ 5 = −5
                                                    α •12•2 = α •112γ 12 + α •122γ 22 = 2 ⋅ (−3) + 5 ⋅ 2 = 4
                                                    α •21
                                                        •2 = α •12γ
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                                                    α •22
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                                                                    + α •222γ 22 = 1 ⋅ (−3) + 3 ⋅ 2 = 3.
                                                                                     
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