Конспект лекций по статистической физике. Коренблит С.Э - 111 стр.

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3   “à ¢­¥­¨ï á®áâ®ï­¨ï ä®â®­­®£® £ §
    ®áª®«ìªã  = 0, â®, ª ª ¤«ï á¨á⥬ë á ­ã«¥¢ë¬ ¯®â¥­æ¨ «®¬ ƒ¨¡¡á
 = 0, ¨¬¥¥¬: F = J + N =) J = PV , ®âªã¤ (@P=@V )T =) 0, ¯à¨:
                 !                   !
    P  @V =!!!) P (T ); @V  T dPdT(T ) P (T ) =!!!) VU ; (11.23)
             @F                  @U
                   T                  T
  , ­ «®£¨ç­®¥ (10.6), ¨­â¥£à¨à®¢ ­¨¥ ¯® ç áâï¬, ¯® ç áâ®â ¬ d!, ¯à¨-
¢®¤¨â ª ᮮ⢥âáâ¢ãî饬ã ãà ¢­¥­¨î á®áâ®ï­¨ï ä®â®­­®£® £ § ¢ ¢¨¤¥:
   dP! (T ) = 1 dE! (T ) = 1 u(!; T ); P (T ) = 1 U  1 <>: (11.24)
     d!        3V d!        3                    3V 3
¥è¥­¨¥ íâ¨å ãà ¢­¥­¨© (11.23), (11.24) ¬®¦­® ¢®á¯à®¨§¢¥á⨠­¥¯®á।-
á⢥­­ë¬ ¨­â¥£à¨à®¢ ­¨¥¬ (11.20), (11.21), á ãç¥â®¬ (10.10){(10.14):
                   Z           V   Z1     ! 2 d!        V (kB T )3
 nV  <> = dN! (T ) = 2 c3 exp(h!=k T ) 1 = 2(hc)3 I3; (11.25)
                                   0           B
                 Z          V   Z1
                               h        ! 3 d!        V (kB T )4
 U  <> = dE! (T ) = 2c3 exp(h!=k T ) 1 = 2(hc)3 I4; (11.26)
                                 0           B
             1
            Z xs 1 dx                         1 1
                                              X
 £¤¥: Is = exp(      x) 1
                          = (s)s(1) = (s) s = (s) (s);
                                                 `                 (11.27)
            0                                `=1
 â® ¥áâì: I = (4) (4) =   6; 49; I = (3) (3)  2; 40;
                             4
           4                           3                           (11.28)
                          15
¨, ¯®¤áâ ¢¨¢ ¢ (11.26), ¯®«ãç¨âì § ª®­ ¨ ª®­áâ ­â㠑â¥ä ­ { ®«ìæ¬ ­
                      2k4
  U = T V;  = 15(hcB)3 = 7; 56  10 15 í࣠ ᬠ3  Š 4; â.ª.: (11.29)
         4

                  U              U    F         @P !
     F =) PV = 3 ; â® ¨: S  T = V @T =) 43 T 3 V; (11.30)
                                                  V
{ í­âய¨î ä®â®­­®£® £ § , 㤮¢«¥â¢®àïîéãî § ª®­ã ¥à­áâ : S T !!0 0 :
    „«ï í­¥à£¨¨, ¯à¨å®¤ï饩áï ¢ á।­¥¬ ­ ®¤­ã \ç áâ¨æã", ¨¬¥¥¬:
   <> = I4 k T = 3  (4) k T; <> = P =  (4) n(T )k T; (11.31)
   <> I3 B             (3) B       3          (3)       B
           (4)  0; 900: ޤ­ ª®: I4 7 ! 3; ¨ U  k T;
   £¤¥:  (3)                   I3         3<> B
                                                                 (11.32)