Интегральное исчисление. Определенный интеграл - 41 стр.

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T [a, b] I {x
0
i
, ξ
0
i
}
T
0
[a + kτ, b + kτ] x
0
i
= x
i
+ kτ
ξ
0
i
= ξ
i
+ kτ
x
0
i
= x
i
i = 1, 2, . . . , n I {x
0
i
, ξ
0
i
} =
I {x
i
, ξ
i
} f
I {x
0
i
, ξ
0
i
} =
n
X
i=1
f (ξ
0
i
) x
0
i
=
n
X
i=1
f (ξ
i
+ kτ) x
i
=
=
n
X
i=1
f (ξ
i
) x
i
= I {x
i
, ξ
i
}.
f τ
[α, β] R
a+τ
Z
a
f(x) dx =
τ
Z
0
f(x) dx
a R
a R k Z kτ
a < (k + 1)τ
a = kτ a + τ = (k + 1)τ
a+τ
Z
a
f(x) dx =
τ+kτ
Z
0+
f(x) dx =
τ
Z
0
f(x) dx.
a 6= kτ kτ < a < (k + 1)τ = kτ + τ < a + τ < (k + 1)τ + τ
a+τ
Z
a
f(x) dx =
+τ
Z
a
f(x) dx +
a+τ
Z
(k+1)τ
f(x) dx =
τ+kτ
Z
(a )+
f(x) dx+
+
(a )+(k+1)τ
Z
0+(k+1)τ
f(x) dx =
τ
Z
a
f(x) dx +
a
Z
0
f(x) dx =
τ
Z
0
f(x) dx.