Интегральное исчисление. Неопределенный интеграл - 25 стр.

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u = t dv =
t dt
(t
2
+ 1)
β
du = dt v =
1
(β 1) (t
2
+ 1)
β1
K
β
= K
β1
+
t
2 (β 1) (t
2
+ 1)
β1
1
2 (β 1)
Z
dt
(t
2
+ 1)
β1
=
=
t
2 (β 1) (t
2
+ 1)
β1
+
2β 3
2 (β 1)
K
β1
.
x
Z
x + 3
(x 1)(x
2
+ 1)
2
dx .
Z
x + 3
(x 1)(x
2
+ 1)
2
dx =
Z
dx
x 1
Z
x + 1
x
2
+ 1
dx
Z
2x + 1
(x
2
+ 1)
2
dx =
= ln |x 1|
1
2
Z
2x dx
x
2
+ 1
Z
dx
x
2
+ 1
Z
2x dx
(x
2
+ 1)
2
Z
dx
(x
2
+ 1)
2
=
= ln |x 1|
1
2
ln(x
2
+ 1) arctg x +
1
x
2
+ 1
x
2(x
2
+ 1)
1
2
Z
dx
x
2
+ 1
=
= ln |x 1|
1
2
ln(x
2
+ 1)
3
2
arctg x +
1
x
2
+ 1
x
2(x
2
+ 1)
+ C.
Z
3x
4
+ 7x
3
+ x
2
x 2
x
4
1
dx .
Z
3x
4
+ 7x
3
+ x
2
x 2
x
4
1
dx =
Z
µ
3 +
7x
3
+ x
2
x + 1
x
4
1
dx.