Методы и средства исследования технологических процессов ткацкого производства. Назарова М.В - 122 стр.

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()() ()() ()()
()() ()() ()()
()() ()() ()
()
() ()
;83,0
8
6,6
7,291)0(6,281)0(
7,25)0()0(3,30)0()0(7,23)0(1
7,17)0(10,28110,2811
7,28114,22113,2811
2,25111,28115,3111
8
1
b
13
==+++
++++
++++++
++++++
++++++++=
]
[
()() ()() ()()
()() ()() ()()
()() ()()
() ()
() ()
;38,1
8
0,11
7,291)0(6,281)0(
7,25)0(13,30)0(17,23)0()0(
7,17)0()0(0,28110,2811
7,28114,22113,2811
2,25111,28115,3111
8
1
b
23
==+++
+++++
++++
+++++++
++++++++=
]
[
()
() ()
;46,47,2092,3876,13
]7,29)0(6,28)0(7,25)0(3,30)0(7,2317,171[
2
1
)7,296,287,253,307,237,17(
4
1
0,280,287,284,223,282,251,285,31
16
1
b
22
11
=+=
=+++++++
++++++
+++++++=
            1
     b 13 =   ⋅ [ (+ 1 ) ⋅ (+ 1 ) ⋅ 31 ,5 + (− 1 ) ⋅ (+ 1 ) ⋅ 28 ,1 + (+ 1) ⋅ (+ 1) ⋅ 25 , 2 +
            8
         + (− 1) ⋅ (+ 1) ⋅ 28 ,3 + (+ 1) ⋅ (− 1 ) ⋅ 22 , 4 + (− 1) ⋅ (− 1) ⋅ 28 , 7 +
          + (+ 1 ) ⋅ (− 1) ⋅ 28 , 0 + (− 1 ) ⋅ (− 1) ⋅ 28 , 0 + (+ 1 ) ⋅ ( 0 ) ⋅ 17 , 7 +
              + (− 1 ) ⋅ ( 0 ) ⋅ 23 , 7 + ( 0 ) ⋅ ( 0 ) ⋅ 30 ,3 + ( 0 ) ⋅ ( 0 ) ⋅ 25 , 7 +
                                                                        6 ,6
              + ( 0 ) ⋅ (+ 1 ) ⋅ 28 , 6 + ( 0 ) ⋅ (− 1) ⋅ 29 , 7 ] =         = 0 ,83 ;
                                                                         8
                1
        b 23 = ⋅ [(+ 1) ⋅ (+ 1) ⋅ 31,5 + (+ 1) ⋅ (+ 1) ⋅ 28,1 + (− 1) ⋅ (+ 1) ⋅ 25,2 +
                8
             + (− 1) ⋅ (+ 1) ⋅ 28,3 + (+ 1) ⋅ (− 1) ⋅ 22,4 + (+ 1) ⋅ (− 1) ⋅ 28,7 +
            + (− 1) ⋅ (− 1) ⋅ 28,0 + (− 1) ⋅ (− 1) ⋅ 28,0 + (0) ⋅ (0) ⋅ 17,7 +
              + (0) ⋅ (0) ⋅ 23,7 + (+ 1) ⋅ (0) ⋅ 30,3 + (− 1) ⋅ (0) ⋅ 25,7 +
                                                             11,0
               + (0) ⋅ (+ 1) ⋅ 28,6 + (0) ⋅ (− 1) ⋅ 29,7] =         = 1,38;
                                                               8
            1
      b11 = ⋅ (31,5 + 28,1 + 25,2 + 28,3 + 22,4 + 28,7 + 28,0 + 28,0 ) −
           16
                 1
               − ⋅ (17,7 + 23,7 + 30,3 + 25,7 + 28,6 + 29,7) +
                 4
 1
+ [(+ 1) ⋅ 17,7 + (− 1) ⋅ 23,7 + (0) ⋅ 30,3 + (0) ⋅ 25,7 + (0) ⋅ 28,6 + (0) ⋅ 29,7] =
        2              2

 2
                       = 13,76 − 38,92 + 20,7 = −4,46;