Электродинамика. Нетребко Н.В - 308 стр.

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§15. Ответы
308
12.31.
( )
( )
+
+
++
=
21
2
21
22
10
1
cos
1
CCR
arctgt
CCR
CE
I
R
ω
ω
ω
ω
,
( )
( )
+
+
++
+
=
1
212
2
21
22
2
2
22
10
cos
1
1
1
C
CCRC
arctgt
CCR
CRCE
I
C
ω
ω
ω
ωω
.
12.32.
1) r
LC
1
=
ω
любое, 2)
ω
C
L
r = любая.
12.33.
( )
( )
2
2
2
2
0
/1
/1
CLR
CLR
UV
ωω
ωω
+
++
= .
12.34.
0
=
W
12.35.
222
222
2
0
2
2
2
,
1
LR
LR
R
U
W
L
C
ω
ω
ω
+
+
== .
12.36.
(
)
( )
LCR
CRL
arctg
2
2
1
ω
ω
ϕ
+
=
12.37.
(
)
( )
CRL
LCR
arctg
2
2
1
+
=
ω
ω
ϕ
12.38.
1
2
222
=
Cr
rC
arctg
ω
ω
ϕ
12.39.
ϕ
π
ψ
=
12.40.
( )
2
20
2
23
2
0
203201
,,
+
=+=+=
LL
L
CC
L
L
LLLLLL .
308                                                                                          §15. Ответы

                               E 0ωC1                                      1          
12.31. I R =                                           cos ωt + arctg                ,
                    1 + ω 2 R 2 (C1 + C 2 )2                           ωR(C1 + C 2 ) 

         E 0ωC1 1 + ω 2 R 2 C 22                               ωRC 2 (C1 + C 2 ) 
I C1 =                                         cos ωt + arctg                    .
          1 + ω 2 R 2 (C1 + C 2 )          2
                                                                     C1           


                          1                                          L
12.32. 1) ω =                          r любое,             2) r =           ω любая.
                          LC                                         C

                      R 2 + (ω L + 1 / ω C )2
12.33. V = U 0                                          .
                      R 2 + (ω L − 1 / ω C )2
12.34. W = 0
                1                          U 02 2 R 2 + ω 2 L2
12.35. C =            ,         W =            ⋅               .
              ω 2L                         2 R R 2 + ω 2 L2

12.36. ϕ = arctg
                     (        )
                          ω L − R 2C
                    (          )
                          R 1 + ω 2 LC

                    R (1 + ω LC )      2
12.37.    ϕ = arctg
                    ω (L − R C )           2


                               2ωrC
12.38. ϕ = arctg
                ω r C 2 −1    2 2

12.39. ψ = π − ϕ
                                                                                         2
                                                   L                L2              
12.40. L1 = L0 + L2 ,               L3 = (L0 + L2 ) 0 , C 3 = C 2                   .
                                                                                     
                                                   L2               L0 + L2         