Анализ прохождения сигналов через линейные цепи. Парфенов В.И. - 16 стр.

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16
6.
τεετ
τττ
τττ
====⋅
===⋅
===⋅
−−
−−
RCRCRC
1122111
4
2
4
3
4
4
3
5
3
6
3
7
3
5702510
82261099410170910
255210399310401510
,/,,.,
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7.
τεετ
τττ
τττ
====⋅
===⋅
===⋅
−−
−−
LRLRLR
1121121
4
2
4
3
4
4
3
5
3
6
3
7
3
05724310
834410955610124210
269810322710403810
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8.
τεετ
τττ
τττ
====⋅
===⋅
===
−−
LRLRLR
1121121
3
2
3
3
3
4
3
5
3
6
7
01577510
609410719510822710
90051000195002015
/,/,.,.,
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9.
τεετ
τττ
τττ
====⋅
===⋅
===⋅
−−
−−
RCLRCR
1121
4
2
4
3
4
4
4
5
4
6
4
7
4
10312510
492110534510610710
743910812710945510
,/,,.,
.,.,.,
.,.,.
10.
τεετ
τττ
τττ
====⋅
===⋅
===⋅
−−
−−
RCLRCR
1211
4
2
4
3
4
4
4
5
4
6
3
7
3
325598410
612910735510809210
915710110710295510
,/,.,.,
.,.,.,
.,.,.
11.
τεετ
τττ
τττ
====⋅
===⋅
===⋅
−−
−−
LRCRRL/,/,,.,
.,.,.,
.,.,.
1121
3
2
3
3
3
4
3
5
3
6
3
7
3
1108510
247610326510497610
556810634510722210
12.
τεετ
τττ
τττ
====⋅
===⋅
===⋅
−−
−−
LRCRRL/,/,.,.,
.,.,.,
.,.,.
1121
3
2
3
3
3
4
3
5
3
6
3
7
3
015176710
259110324810458710
510410639610785310
                       16
        τ = R1C1, ε = R 2C 2 / R1C1, ε = 5, τ1 = 7.025 ⋅ 10 −4 ,
6.      τ 2 = 8.226 ⋅ 10 −4 , τ3 = 9.94 ⋅ 10 −4 , τ 4 = 1709
                                                         .   ⋅ 10 −3 ,
        τ5 = 2.552 ⋅ 10 −3 , τ 6 = 3.993 ⋅ 10 −3 , τ 7 = 4.015 ⋅ 10 −3

      τ = L 1 / R1, ε = L 2 R1 / L 1R 2 , ε = 0.5, τ1 = 7.243 ⋅ 10 −4 ,
7.    τ 2 = 8.344 ⋅ 10 −4 , τ3 = 9.556 ⋅ 10 −4 , τ 4 = 1242
                                                        .   ⋅ 10 −3 ,
      τ5 = 2.698 ⋅ 10 −3 , τ 6 = 3.227 ⋅ 10 −3 , τ 7 = 4.038 ⋅ 10 −3

                                               . , τ1 = 5.775 ⋅ 10 −3 ,
         τ = L1 / R1, ε = L 2R1 / L1R 2 , ε = 01
8.       τ2 = 6.094 ⋅10 −3 , τ3 = 7195
                                   .   ⋅10 −3 , τ4 = 8.227 ⋅10 −3 ,
         τ5 = 9.005 ⋅10 −3 , τ 6 = 0.0195, τ 7 = 0.02015

       τ = R1C , ε = L / R1CR 2 , ε = 10, τ1 = 3125   .   ⋅ 10 −4 ,
9.     τ 2 = 4.921 ⋅ 10 −4 , τ 3 = 5.345 ⋅ 10 −4 , τ 4 = 6107
                                                          .     ⋅ 10 −4 ,
       τ5 = 7.439 ⋅ 10 −4 , τ 6 = 8127
                                   .   ⋅ 10 −4 , τ 7 = 9.455 ⋅ 10 −4

       τ = R1C , ε = L / R 2CR1, ε = 3.25, τ1 = 5.984 ⋅ 10 −4 ,
10.    τ 2 = 6129
              .    ⋅ 10 −4 , τ3 = 7.355 ⋅ 10 −4 , τ 4 = 8.092 ⋅ 10 −4 ,
       τ5 = 9.157 ⋅ 10 −4 , τ 6 = 1107
                                   .   ⋅ 10 −3 , τ 7 = 2.955 ⋅ 10 −3

       τ = L / R1, ε = CR1R 2 / L , ε = 1, τ1 = 1085  .    ⋅ 10 −3 ,
11.    τ 2 = 2.476 ⋅ 10 −3 , τ 3 = 3.265 ⋅ 10 −3 , τ 4 = 4.976 ⋅ 10 −3 ,
       τ5 = 5.568 ⋅ 10 −3 , τ 6 = 6.345 ⋅ 10 −3 , τ 7 = 7.222 ⋅ 10 −3

        τ = L / R1, ε = CR1R 2 / L , ε = 0.15, τ1 = 1767
                                                     .   ⋅ 10 −3 ,
12.     τ 2 = 2.591 ⋅ 10 −3 , τ 3 = 3.248 ⋅ 10 −3 , τ 4 = 4.587 ⋅ 10 −3 ,
        τ5 = 5104
              .   ⋅ 10 −3 , τ 6 = 6.396 ⋅ 10 −3 , τ 7 = 7.853 ⋅ 10 −3