Линейная алгебра. Постникова Л.С - 24 стр.

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24
9
{}
lll l
lll
llll
x
112 3
212
3123
6
5
6
10 5 1
=++
=−
=− + +
= ;;
10
{}
lll l
lll
llll
x
112 3
212
3123
7
7
6
16 12
=++
=−
=− + +
= ;;
11
{}
lll l
lll
llll
x
112 3
212
3123
7
6
7
12 6 1
=++
=−
=− + +
=− ;;
12
{}
lll l
lll
llll
x
112 3
212
3123
8
8
7
17 14
=++
=−
=− + +
=−;;
13
{}
llll
lll
llll
x
1123
212
3123
1
2
324
=+
=−
=− + +
=−;;
14
{}
lll l
lll
llll
x
11 3
212
3123
1
2
243
=++
=−
=− + +
= ;;
15
{}
lll l
lll
llll
x
112 3
212
3123
2
2
3
26 3
=+
=−
=− + +
=−;;
16
{}
lll l
lll
llll
x
112 3
212
3123
2
3
2
12 3 1
=++
=−
=− + +
=−;;
17
{}
lll l
lll
llll
x
112 3
212
3123
3
3
4
148
=+
=−
=− + +
=−;;
18
{}
lll l
lll
llll
x
112 3
212
3123
3
3
4
14 8
=+
=−
=− + +
=−;;
                              24


9                   6
     l1′ = l1 + l2 + l3
                                   10   l1′ = l1 + l2 + 7 l3
                    5
                                                 7
                                        l2 ′ =     l1 − l2
     l ′ = 6l − l
     2        1    2                             6
     l3 ′ = − l1 + l2 + l3              l3 ′ = − l1 + l2 + l3
     x = {10 ;5;1}                      x = {1;6 ;12}
11                  7
     l1′ = l1 + l2 + l3
                                   12   l1′ = l1 + l2 + 8 l3
                    6
                                                 8
                                        l2 ′ =     l1 − l2
     l ′ = 7l − l
     2       1     2                             7
     l3 ′ = − l1 + l2 + l3              l3 ′ = − l1 + l2 + l3
     x = {− 12;6 ;1}                    x = {− 1;7 ;14}
13   l1′ = l1 + l2 − l3            14                 1
                                        l1′ = l1 + l + l3
                                                      2
           1
     l2 ′ = l1 − l2
           2                            l ′ = −l − l
                                        2          1       2

     l ′ = −l + l + l
     3        1    2      3             l3 ′ = − l1 + l2 + l3
     x = {− 3;2;4}                      x = {2;4;3}
15   l1′ = l1 + l2 − 2l3           16                  2
                                        l1′ = l1 + l2 + l3
                                                       3
           2
     l2 ′ = l1 − l2
           3                            l ′ = −2 l − l
                                        2              1       2

     l ′ = −l + l + l
     3        1    2      3             l3 ′ = − l1 + l2 + l3
     x = {2;6 ;−3}                      x = {12;3;−1}
17   l1′ = l1 + l2 − 3l3           18   l1′ = l1 + l2 − 3l3
           3                                  3
     l2 ′ = l1 − l2                     l2 ′ = l1 − l2
           4                                  4
     l ′ = −l + l + l
     3        1    2      3             l ′ = −l + l + l
                                        3          1       2       3
     x = {1;−4;8}                       x = {1;4;−8}